在我致力于疯人院之前,我想我会尝试一下:你如何编写代码来打印多个页面?
我一直在尝试我在stackoverflow(和其他地方)找到的所有例子,但我没有取得任何成功!这让我比以前更疯狂!我发现的所有其他例子都是处理与我想要做的事情无关的问题.我试图修复的示例将在两个页面上打印0-100个整数,即第1页的0-80和第2页的81-100.尽管所有我建议的技术都是一页被页面覆盖的页面2的数据在顶部.
e.HasMorePages = true; 应该开始下一页但不起作用.
我为此创建了一个非常简单的Winform程序,这是代码.任何想法将不胜感激:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Drawing.Printing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Collections;
namespace PrintMultiplePages_v2
{
public partial class Form1 : Form
{
ArrayList al = new ArrayList();
private int fontcount;
private int fontposition = 1;
private float ypos;
private string textToPrint;
private PrintPreviewDialog previewDlg = null;
private PrintDocument pd = null;
private int counter = 0;
private int amtperpage = 80; // The amount of lines per page
public Form1()
{
InitializeComponent();
for (int i = 0; i < 100; i++)
al.Add(i.ToString());
}
private void buttonPrint_Click(object sender, EventArgs e)
{
PrintDocument pd = new PrintDocument();
pd.PrintPage += new PrintPageEventHandler(pd_PrintPage);
pd.Print();
}
private void pd_PrintPage(object sender, PrintPageEventArgs e)
{
float leftMargin = 70.0f;
float topMargin = 20.0f;
float lineInc = 20.0f;
Font printFontArial10 = new Font("Arial", 10, FontStyle.Regular);
Graphics g = e.Graphics;
double pageCount = (double)al.Count / (double)amtperpage;
int pageRequired = Convert.ToInt32(Math.Ceiling(pageCount));
counter = 0;
for (int page = 1; page <= pageRequired; page++)
{
int counterMax = amtperpage * page;
if (counterMax > al.Count)
counterMax = al.Count;
for (int x = counter; x < counterMax; x++)
{
textToPrint = al[x].ToString() + " - test";
e.Graphics.DrawString(textToPrint, printFontArial10, Brushes.Black, leftMargin, topMargin + lineInc);
lineInc += 12;
counter++;
}
if (counter == counterMax)
{
if (counter != al.Count)
{
e.HasMorePages = true;
counter++;
lineInc = 20.0f;
}
}
else
e.HasMorePages = false;
}
}
}
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}
更正的代码是:
private int page = 0;
private void buttonPrint_Click(object sender, EventArgs e)
{
page = 0;
PrintDocument pd = new PrintDocument();
pd.PrintPage += new PrintPageEventHandler(pd_PrintPage);
pd.Print();
}
private void pd_PrintPage(object sender, PrintPageEventArgs e)
{
float leftMargin = 70.0f;
float topMargin = 20.0f;
float lineInc = 20.0f;
Font printFontArial10 = new Font("Arial", 10, FontStyle.Regular);
Graphics g = e.Graphics;
int stop = counter + amtperpage;
if (stop > al.Count)
stop = al.Count;
while (counter < stop)
{
textToPrint = al[counter].ToString() + " - test";
e.Graphics.DrawString(textToPrint, printFontArial10, Brushes.Black, leftMargin, topMargin + lineInc);
lineInc += 12;
counter++;
}
page++;
e.HasMorePages = counter < al.Count;
}
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应该重复调用PrintPage事件,直到e.HasMorePages变为false.这个事件取决于一次打印一页.你只需要调用一次,然后在一个for循环中将它们送到两个页面.换句话说,for循环正在杀死你.从逻辑上讲,您应该跟踪当前所在的页面(pd_PrintPage之外)并在继续时递增计数器.你可以告诉你有这个错误,因为在 pd_PrintPage中计数器被设置为零,而在buttonPrint_Click中应该设置为零.
所以从pd_PrintPage中拉出"int page"并使循环类似于
int stop = counter + amtperpage;
if (stop >= al.Count)
stop = al.Count - 1; // - 1 to prevent index out of range error.
while (counter <= stop)
{
textToPrint = al[counter].ToString() + " - test";
e.Graphics.DrawString(textToPrint, printFontArial10, Brushes.Black, leftMargin, topMargin + lineInc);
lineInc += 12;
counter++;
}
page++;
e.HasMorePages = counter < al.Count - 1; // pesky zero-based array issue again.
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