通过Python在VLC中打开视频文件

Question

import subprocess
import os
print os.path.exists("C:/Users/Dhruv/Desktop/Motivation/RiseShine.mp4") 
p = subprocess.Popen(["C:/Program Files (x86)/VideoLAN/VLC/vlc.exe","C:/Users/Dhruv/Desktop/Motivation/RiseShine.mp4"])

上面的代码是使用python在VLC播放器中打开一个视频文件.VLC播放器打开,但不运行视频.我查了一下视频位置,这是对的.有人可以告诉我如何使这项工作？

Answer 1

这对我有用(Python 3.4):

p = subprocess.Popen(["C:/Program Files (x86)/VideoLAN/VLC/vlc.exe","\\E:\Movies\\" + title + '.mp4'])

测试的视频绝对是mp4格式,顺便说一下.