获取当前季度php的startdate和enddate

Question

我试图按季度设置开始日期和结束日期.

例如,我正在开发一个报告系统,我需要报告第1季度,第2季度,第3季度和第4季度的数据.

第一季度 - 1月至3月

第二季度 - 四月至六月

第三季度 - 七月至九月

第四季度 - 十月至十二月

例如,我有一些当月和上个月的案例,如下所示.

   case 'this_month':
      $start_date = date(DATE_FORMAT, mktime(0, 0, 0, date("m"), 1, date("Y")));
      $end_date = date(DATE_FORMAT, mktime(0, 0, 0, date("m"), date("d"), date("Y")));
    break;
    case 'last_month':
      $start_date = date(DATE_FORMAT, mktime(0, 0, 0, date("m") - 1, 1, date("Y")));
      $end_date = date(DATE_FORMAT, mktime(0, 0, 0, date("m"), 0, date("Y")));
    break;

但现在我需要为此和上个季度添加案例,我不确定如何实际这样做,因此它反映了适当的季度范围.

有任何想法吗？

Answer 1

/**
* Compute the start and end date of some fixed o relative quarter in a specific year.
* @param mixed $quarter  Integer from 1 to 4 or relative string value:
*                        'this', 'current', 'previous', 'first' or 'last'.
*                        'this' is equivalent to 'current'. Any other value
*                        will be ignored and instead current quarter will be used.
*                        Default value 'current'. Particulary, 'previous' value
*                        only make sense with current year so if you use it with
*                        other year like: get_dates_of_quarter('previous', 1990)
*                        the year will be ignored and instead the current year
*                        will be used.
* @param int $year       Year of the quarter. Any wrong value will be ignored and
*                        instead the current year will be used.
*                        Default value null (current year).
* @param string $format  String to format returned dates
* @return array          Array with two elements (keys): start and end date.
*/
public static function get_dates_of_quarter($quarter = 'current', $year = null, $format = null)
{
    if ( !is_int($year) ) {        
       $year = (new DateTime)->format('Y');
    }
    $current_quarter = ceil((new DateTime)->format('n') / 3);
    switch (  strtolower($quarter) ) {
    case 'this':
    case 'current':
       $quarter = ceil((new DateTime)->format('n') / 3);
       break;

    case 'previous':
       $year = (new DateTime)->format('Y');
       if ($current_quarter == 1) {
          $quarter = 4;
          $year--;
        } else {
          $quarter =  $current_quarter - 1;
        }
        break;

    case 'first':
        $quarter = 1;
        break;

    case 'last':
        $quarter = 4;
        break;

    default:
        $quarter = (!is_int($quarter) || $quarter < 1 || $quarter > 4) ? $current_quarter : $quarter;
        break;
    }
    if ( $quarter === 'this' ) {
        $quarter = ceil((new DateTime)->format('n') / 3);
    }
    $start = new DateTime($year.'-'.(3*$quarter-2).'-1 00:00:00');
    $end = new DateTime($year.'-'.(3*$quarter).'-'.($quarter == 1 || $quarter == 4 ? 31 : 30) .' 23:59:59');

    return array(
        'start' => $format ? $start->format($format) : $start,
        'end' => $format ? $end->format($format) : $end,
    );
}

我开发此函数以任何方式处理季度:相对(this,previous,first,last)和fixed.

例子:

get_dates_of_quarter();
//return current quarter start and end dates

get_dates_of_quarter(2);
//return 2nd quarter start and end dates of current year

get_dates_of_quarter('first', 2010, 'Y-m-d');
//return start='2010-01-01' and end='2014-03-31'

get_dates_of_quarter('current', 2009, 'Y-m-d');
//Supposing today is '2014-08-22' (3rd quarter), this will return
//3rd quarter but of year 2009.
//return start='2009-07-01' and end='2009-09-30'

get_dates_of_quarter('previous');
//Supposing today is '2014-02-18' (1st quarter), this will return
//return start='2013-10-01' and end='2013-12-31'

等待这个帮助某人;)

Answer 2

关于什么:

$offset = (date('n')%3)-1; // modulo ftw
$start = new DateTime("first day of -$offset month midnight");
$offset = 3-(date('n')%3); // modulo ftw again
$end = new DateTime("last day of +$offset month midnight");

Answer 3

简单代码:

$current_quarter = ceil(date('n') / 3);
$first_date = date('Y-m-d', strtotime(date('Y') . '-' . (($current_quarter * 3) - 2) . '-1'));
$last_date = date('Y-m-t', strtotime(date('Y') . '-' . (($current_quarter * 3)) . '-1'));

Answer 4

检查一下this quarter.

 case 'this_quarter':

          $current_month = date('m');
          $current_year = date('Y');
          if($current_month>=1 && $current_month<=3)
          {
            $start_date = strtotime('1-January-'.$current_year);  // timestamp or 1-Januray 12:00:00 AM
            $end_date = strtotime('1-April-'.$current_year);  // timestamp or 1-April 12:00:00 AM means end of 31 March
          }
          else  if($current_month>=4 && $current_month<=6)
          {
            $start_date = strtotime('1-April-'.$current_year);  // timestamp or 1-April 12:00:00 AM
            $end_date = strtotime('1-July-'.$current_year);  // timestamp or 1-July 12:00:00 AM means end of 30 June
          }
          else  if($current_month>=7 && $current_month<=9)
          {
            $start_date = strtotime('1-July-'.$current_year);  // timestamp or 1-July 12:00:00 AM
            $end_date = strtotime('1-October-'.$current_year);  // timestamp or 1-October 12:00:00 AM means end of 30 September
          }
          else  if($current_month>=10 && $current_month<=12)
          {
            $start_date = strtotime('1-October-'.$current_year);  // timestamp or 1-October 12:00:00 AM
            $end_date = strtotime('1-January-'.($current_year+1));  // timestamp or 1-January Next year 12:00:00 AM means end of 31 December this year
          }



        break;

更新:2 和last quarter

case 'last_quarter':

          $current_month = date('m');
          $current_year = date('Y');

          if($current_month>=1 && $current_month<=3)
          {
            $start_date = strtotime('1-October-'.($current_year-1));  // timestamp or 1-October Last Year 12:00:00 AM
            $end_date = strtotime('1-January-'.$current_year);  // // timestamp or 1-January  12:00:00 AM means end of 31 December Last year
          } 
          else if($current_month>=4 && $current_month<=6)
          {
            $start_date = strtotime('1-January-'.$current_year);  // timestamp or 1-Januray 12:00:00 AM
            $end_date = strtotime('1-April-'.$current_year);  // timestamp or 1-April 12:00:00 AM means end of 31 March
          }
          else  if($current_month>=7 && $current_month<=9)
          {
            $start_date = strtotime('1-April-'.$current_year);  // timestamp or 1-April 12:00:00 AM
            $end_date = strtotime('1-July-'.$current_year);  // timestamp or 1-July 12:00:00 AM means end of 30 June
          }
          else  if($current_month>=10 && $current_month<=12)
          {
            $start_date = strtotime('1-July-'.$current_year);  // timestamp or 1-July 12:00:00 AM
            $end_date = strtotime('1-October-'.$current_year);  // timestamp or 1-October 12:00:00 AM means end of 30 September
          }



        break;

Answer 5

IMO的某些答案过于复杂

public function getStartOfQuarter()
{
     return date(sprintf('Y-%s-01', floor((date('n') - 1) / 3) * 3 + 1));
}

public function getEndOfQuarter()
{
    return date(sprintf('Y-%s-t', floor((date('n') + 2) / 3) * 3));
}