应用程序间音频:甚至无法连接我的节点

Question

好吧,我正在尝试将IAA应用到我的iOS应用程序中,并仔细研究了Apple"InterAppAudioSuite"以及WWDCXIII 602视频.我的应用程序就像Apple InterAppAudioSampler,我从这个例子中使用了尽可能多的代码.

我的应用程序启动,我在日志窗口中收到一条"AudioOutputUnitPublish stub"消息,上面写着 - 我想 - 事情还可以.然后,我从Apple启动"InterAppAudioHost"应用程序并尝试连接我的应用程序(充当音频远程仪器).我的应用程序可在应用程序列表中找到.但后来它无法连接,我得到以下日志:

2014-01-16 11:10:27.556 DM1[141:60b] Could not search: {
    NSNetServicesErrorCode = "-72000";
    NSNetServicesErrorDomain = 10;
}
2014-01-16 11:10:27.558 DM1[141:60b] Could not publish service: {
    NSNetServicesErrorCode = "-72000";
    NSNetServicesErrorDomain = 10;
}

(我的应用程序中没有调用任何与IAA相关的方法.)

然后"InterAppAudioHost"退出,其日志显示:

2014-01-16 11:10:47.555 IAA Host[150:60b] 11:10:47.554 ERROR:     [0x3b2e718c] 168: Timed out waiting for app to launch
2014-01-16 11:10:47.557 IAA Host[150:60b] 11:10:47.557 ERROR:     [0x3b2e718c] >audiocomp> 59: null from factory proc
2014-01-16 11:10:47.559 IAA Host[150:60b] error -1 from AUGraphAddNode (hostGraph, &desc, &instrumentNode)

我仔细检查了我的plist,结果如下:

<plist version="1.0">
<dict>
    <key>AudioComponents</key>
    <array>
        <dict>
            <key>type</key>
            <string>aurg</string>
            <key>subtype</key>
            <string>fld1</string>
            <key>manufacturer</key>
            <string>fglb</string>
            <key>name</key>
            <string>appName<string>
            <key>version</key>
            <integer>1</integer>
        </dict>
        <dict>
            <key>type</key>
            <string>auri</string>
            <key>subtype</key>
            <string>fld1</string>
            <key>manufacturer</key>
            <string>fglb</string>
            <key>name</key>
            <string>appName</string>
            <key>version</key>
            <integer>1</integer>
        </dict>
    </array>

...

我的发布方法:

- (void) publishOutputAudioUnit {
    OSStatus result;
    const UInt32 version = 1;
    //-----------------------
    //    Publish as Remote Generator
    //-----------------------
    AudioComponentDescription IAAGeneratorDesc = { kAudioUnitType_RemoteGenerator,'fld1','fglb',0,0 };
    result = AudioOutputUnitPublish(&IAAGeneratorDesc, CFSTR("CompanyName : AppName"),version, auRemoteIO);
    if (result != noErr)
        NSLog(@"AudioOutputUnitPublish generator result: %d", (int)result);
    //-----------------------
    //    Publish as Remote Instrument
    //-----------------------
    AudioComponentDescription IAARemoteDesc = { kAudioUnitType_RemoteInstrument,'fld1','fglb',0,0 };
    result = AudioOutputUnitPublish(&IAARemoteDesc, CFSTR("CompanyName : AppName"),version,auRemoteIO);
    if (result != noErr)
         NSLog(@"AudioOutputUnitPublish instrument result: %d", (int)result);
}

看起来主机和节点之间存在一些URL问题,但我无法弄明白.

任何帮助将非常非常非常受欢迎,因为我真的被卡住了.非常感谢.

安德烈

Answer 1

最终它成功了。不知道我是怎么到那里的。这是我当前的代码：

- (void) publishOutputAudioUnit {
    OSStatus result;
    const UInt32 version = 1;
    SoundEngine *se = [SoundEngine instance];
    //-----------------------
    //  Publish as Remote Instrument
    //-----------------------
    AudioComponentDescription remoteDesc = { kAudioUnitType_RemoteInstrument,IAA_SUB_TYPE,IAA_MANUFACTURER,0,0 };
    result = AudioOutputUnitPublish(&remoteDesc, CFSTR(IAA_NAME),version,se->auRemoteIO);
    if (result != noErr) NSLog(@"AudioOutputUnitPublish instrument result: %d", (int)result);
}

您现在还可以使用包含 IAA 连接的 Audiobus SDK。这比自己做要容易得多。