函数strcpy()改变整数数组的值？

Question

我将从我目前的代码开始,其中输入是用户提供的变量:

int current[2] = {-1, -1}, next[2] = {-1, -1};
char *strtok_result = strtok(input, " ");
int i = 0;
while(strtok_result != NULL){
    i++;
    int count = 0;
    char strtok_buffer[2];
    printf("iteration %d-%d: next[0] = %d\n", i, ++count, next[0]);
    strcpy(strtok_buffer, strtok_result);
    printf("iteration %d-%d: next[0] = %d\n", i, ++count, next[0]);

    current[0] = next[0];
    current[1] = next[1];
    next[0] = strtok_buffer[1] - 48;            // ascii conversion, digit to column
    next[1] = toupper(strtok_buffer[0]) - 64;   // --- || ---, letter to row
    printf("iteration %d-%d: next[0] = %d\n\n", i, ++count, next[0]);
    strtok_result = strtok(NULL, " ");
}
return 0;

如果我输入"A1 B2 C3",我希望得到以下输出:

iteration 1-1: next[0] = -1
iteration 1-2: next[0] = -1
iteration 1-3: next[0] = 1

iteration 2-1: next[0] = 1
iteration 2-2: next[0] = 1
iteration 2-3: next[0] = 2

iteration 3-1: next[0] = 2
iteration 3-2: next[0] = 2
iteration 3-3: next[0] = 3

我收到的输出如下所示:

iteration 1-1: next[0] = -1
iteration 1-2: next[0] = -256
iteration 1-3: next[0] = 1

iteration 2-1: next[0] = 1
iteration 2-2: next[0] = 0
iteration 2-3: next[0] = 2

iteration 3-1: next[0] = 2
iteration 3-2: next[0] = 0
iteration 3-3: next[0] = 3

在我看来,在*strcpy执行期间(strtok_buffer,strtok_result);*next [0]的值被改变了.这令我难以置信.我以前遇到过类似的结果,这与内存重叠(术语？)有关,但我不明白为什么会出现这种情况.

任何帮助表示赞赏,我已经盯着自己盲目地试图解决这个问题.

笔记:

• 输入已被确认为"XY XY ..."格式,其中X是alpha,Y是数字.
• 电流[0],电流[1]和下一个[1]不会以任何方式改变.我决定排除这些输出,因此您不必查看2x36行数.

Answer 1

strtok_buffer[2]是不是大到足以容纳令牌"A1","B2"或"C3".不要忘记字符串需要空格来终止空字符.