我正在为 OBJ 文件制作一个文件解析器,所有内容都会进入正确的位置,但由于某种原因它不会运行到文件末尾。
void loader::readIn()
{
//!takes in the all the data and
//!puts in string first.
std::string line;
while(!myFile.eof())
{
linetype = unknown;//enum set to uknown
line.clear(); // clear line
ss.clear(); // clear string stream
std::getline(myFile,line); //intake line , to string line
//found = line.find("v "); //enum to check the line type i,e Face ,vertex
if(line[0] == 'v') //! check to see if the first char is v
{
linetype = vertex;
}
// found = line.find("f ");
if(line[0] == 'f') //! checkl to see if the first char is f
{
linetype = face;
}
// found = line.find("vn ");
if(line[0] == 'vn') //! checkl to see if the first char is vn
{
linetype = vertexNormal;
}
// found = line.find("vt ")
if(line[0] == 'vt') //! checkl to see if the first char is vt
{
linetype = vertexTexture;
}
if(line[0] == ' ' || '#') // if the start of the line is empty or a #
{
line.clear(); //clear line
std::getline(myFile,line); // intake the next line
}
switch(linetype)
{
case vertex: //!stores the verrtex floats in vert.
ss >> vertexFloat[0] >> vertexFloat[1] >> vertexFloat[2];
verts.push_back(new coordinate(vertexFloat[0],vertexFloat[1],vertexFloat[2])); //creates new coord
linetype = unknown;
break;
case face:
int n; // these are the counters for the float arrays
int m;
int b;
n = 0;
m = 0;
b = 0;
int faces[3]; //temperary float array
int faceText[3];
int faceNorm[3];
ss.str(line); //string stream intake line
ss.ignore(1);
while( !ss.eof())
{
ss >> faces[n]; // intake first umber
n++;
if(ss.peek() == '/')
{
ss.ignore(1);
if(ss.peek() != '/')
{
ss >> faceText[m];
m++;
}
}
ss.ignore(1);
ss >> faceNorm[b];
b++;
}
for( int i = 0; i < 3 ; ++i)
{
totalFaces.push_back(faces[i]); // push back all the ints on the correct
faceTexture.push_back(faceText[i]); // vector
faceNormal.push_back(faceNorm[i]);
}
break;
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这是前 3 行代码,然后就停止了。我正在检查totalFaces向量,它接受每组3个中的第一个数字。
**f 1/2/3 4//6 7/8/9
f 1/2/3 4//6 7/8/9
f 1/2/3 4//6 7/8/9
f 1/2/3 4//6 7/8/9
f 1/2/3 4//6 7/8/9
f 1/2/3 4//6 7/8/9
f 1/2/3 4//6 7/8/9
f 1/2/3 4//6 7/8/9
f 1/2/3 4//6 7/8/9**
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是我的 obj 文件。
eof()
检查循环条件是不正确的。这不是一个预测,它表明之前的读取由于 EOF 而失败。例如,即使是空文件也不以.eof
true 开头。
另外,“vn”既不是一个字符也不是两个字符。line[0]
肯定是一个字符,显然不能等于两个字符“vn”。