在POST中出错后重新加载GET

Question

在POST功能中,如果数量包含'字母',我想重新加载GET.我已经尝试了return View();并查看了return Redirect(returnUrl);但是URL有太多的参数.我只是重新加载GET EDITDETAIL

 [Authorize]
    public ActionResult EditDetail(int id, string returnUrl)
    {
        var order = _orderService.GetOrder(id);



 [HttpPost, ActionName("EditDetail"), Authorize]
    public ActionResult EditDetailPOST(int customerId, int? orderId, List<string> productId, List<string> quantity, string returnUrl, string TargetDate)
    {
        QBCustomerRecord customer = _customerService.GetById(customerId);
        if (customer == null)
        {
            throw new InvalidOperationException("The customer id is Invalid.");
        }

        bool quantityContainsLetter = quantity.Any(s => s.Any(Char.IsLetter));

        if (quantityContainsLetter)
        {
            _notifier.Information(T("A letter has been entered for quantity. Please enter a number"));

            return View();
        }

Answer 1

您需要调用RedirectToAction

return RedirectToAction("EditDetail", new { id = 23, returnUrl = "" });

执行GET版本EditDetail.请原谅我,如果我的RouteValueCollection设置错了,我在开会前很快就会做出这个答案!:)

编辑:

好的,我误解了你的要求.为了显示从GET调用中显示的EditDetail视图,您必须调用:

return View("EditDetail")

我假设这是视图的名称,因为您的代码缺少returnEditDetail的GET版本中的语句.

此外,对于POST方法,您可以这样做:

[HttpPost]
[Authorize]
public ActionResult EditDetail(int customerId, int? orderId, List<string> productId, List<string> quantity, string returnUrl, string TargetDate)

由于该方法的签名与GET版本不同,因此可以使用相同的名称重载该方法.不需要ActionName属性.如果你这样做,那么你可以打电话

return View();

在POST方法中,无需传递视图名称.