为什么拒绝连接？

Question

我正在创建一个Web抓取脚本并将其分为四个部分.另外它们都完美无缺,但是当我把它们放在一起时我得到以下错误:urlopen错误[Errno 111]连接被拒绝.我已经看过类似的问题,并尝试用try-except来捕捉错误,但即使这样也行不通.我的所有代码都是:

from selenium import webdriver
import re
import urllib2
site = ""

def phone():
    global site
    site = "https://www." + site
    if "spokeo" in site:
        browser = webdriver.Firefox()
        browser.get(site)
        content = browser.page_source
        browser.quit()
        m_obj = re.search(r"(\(\d{3}\)\s\d{3}-\*{4})", content)
        if m_obj:    
            print m_obj.group(0)    
    elif "addresses" in site:
        usock = urllib2.urlopen(site)
        data = usock.read()
        usock.close()
        m_obj = re.search(r"(\(\d{3}\)\s\d{3}-\d{4})", data)
        if m_obj:    
            print m_obj.group(0)
    else :
        usock = urllib2.urlopen(site)
        data = usock.read()
        usock.close()
        m_obj = re.search(r"(\d{3}-\s\d{3}-\d{4})", data)
        if m_obj:    
            print m_obj.group(0)

def pipl():
    global site
    url = "https://pipl.com/search/?q=tom+jones&l=Phoenix%2C+AZ%2C+US&sloc=US|AZ|Phoenix&in=6"
    usock = urllib2.urlopen(url)
    data = usock.read()
    usock.close()
    r_list = [#re.compile("spokeo.com/[^\s]+"),
             re.compile("addresses.com/[^\s]+"),
             re.compile("10digits.us/[^\s]+")]
    for r in r_list:
        match = re.findall(r,data)
        for site in match:
            site = site[:-6]
            print site
            phone()

pipl()

这是我的追溯:

Traceback (most recent call last):
  File "/home/lazarov/.spyder2/.temp.py", line 48, in <module>
    pipl()
  File "/home/lazarov/.spyder2/.temp.py", line 46, in pipl
    phone()
  File "/home/lazarov/.spyder2/.temp.py", line 25, in phone
    usock = urllib2.urlopen(site)
  File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "/usr/lib/python2.7/urllib2.py", line 400, in open
    response = self._open(req, data)
  File "/usr/lib/python2.7/urllib2.py", line 418, in _open
    '_open', req)
  File "/usr/lib/python2.7/urllib2.py", line 378, in _call_chain
    result = func(*args)
  File "/usr/lib/python2.7/urllib2.py", line 1215, in https_open
    return self.do_open(httplib.HTTPSConnection, req)
  File "/usr/lib/python2.7/urllib2.py", line 1177, in do_open
    raise URLError(err)
urllib2.URLError: <urlopen error [Errno 111] Connection refused>

手动调试代码后,我发现错误来自函数phone(),所以我试着运行那个:

import re
import urllib2
url = 'http://www.10digits.us/n/Tom_Jones/Phoenix_AZ/1fe293a0b7'
usock = urllib2.urlopen(url)
data = usock.read()
usock.close()
m_obj = re.search(r"(\d{3}-\d{3}-\d{4})", data)
if m_obj:
    print m_obj.group(0)

它奏效了.我相信,这表明防火墙并非主动拒绝连接,或者相应的服务未在其他站点上启动或过载.任何帮助都会被贬低.

Answer 1

通常魔鬼在细节.

根据你的追溯......

File "/usr/lib/python2.7/urllib2.py", line 1215, in https_open
return self.do_open(httplib.HTTPSConnection, req)

和你的源代码......

site = "https://www." + site

...我可能会认为在您尝试访问的代码中,https://www.10digits.us/n/Tom_Jones/Phoenix_AZ/1fe293a0b7而在您的测试中,您正在连接到http://www.10digits.us/n/Tom_Jones/Phoenix_AZ/1fe293a0b7.

尝试替换httpswith http(至少为www.10digits.us):可能你试图抓取的网站没有响应端口443而只响应端口80(你甚至可以用你的浏览器检查它)