缓冲/无缓冲通道

Question

有人可以解释一下,为什么如果通道被缓冲,程序不会以fatal_error退出？

无缓冲的频道

package main

func main() {
    c := make(chan int)
    c <- 3
}

fatal error: all goroutines are asleep - deadlock!

缓冲频道

package main

func main() {
    c := make(chan int, 1)
    c <- 3
}

[no output]

Program exited.

谢谢!

Answer 1

如果缓冲区中有空间,则写入缓冲通道不会阻止.

如果您尝试将两个项目放在缓冲区大小为1的通道中,则会出现相同的错误:

package main

func main() {
    c := make(chan int, 1)
    c <- 3
    c <- 4
}

给你:

fatal error: all goroutines are asleep - deadlock!

Answer 2

谢谢@马特

我在这篇文章中找到了答案make(chan bool) 与 make(chan bool, 1) 的行为有何不同？:

Actually that's the reason why your problem is generated. Un-buffered channels are only writable when there's someone blocking to read from it, which means you shall have some coroutines to work with -- instead of this single one.