我从JSON文件"new.json"获取一些数据,我想过滤一些数据并将其存储到一个新的JSON文件中.这是我的代码:
import json
with open('new.json') as infile:
data = json.load(infile)
for item in data:
iden = item.get["id"]
a = item.get["a"]
b = item.get["b"]
c = item.get["c"]
if c == 'XYZ' or "XYZ" in data["text"]:
filename = 'abc.json'
try:
outfile = open(filename,'ab')
except:
outfile = open(filename,'wb')
obj_json={}
obj_json["ID"] = iden
obj_json["VAL_A"] = a
obj_json["VAL_B"] = b
我收到一个错误,追溯是:
File "rtfav.py", line 3, in <module>
data = json.load(infile)
File "/usr/lib64/python2.7/json/__init__.py", line 278, in load
**kw)
File "/usr/lib64/python2.7/json/__init__.py", line 326, in loads
return _default_decoder.decode(s)
File "/usr/lib64/python2.7/json/decoder.py", line 369, in decode
raise ValueError(errmsg("Extra data", s, end, len(s)))
ValueError: Extra data: line 88 column 2 - line 50607 column 2 (char 3077 - 1868399)
有人能帮我吗？
以下是new.json中的数据示例,文件中还有大约1500个这样的词典
{
"contributors": null,
"truncated": false,
"text": "@HomeShop18 #DreamJob to professional rafter",
"in_reply_to_status_id": null,
"id": 421584490452893696,
"favorite_count": 0,
"source": "<a href=\"https://mobile.twitter.com\" rel=\"nofollow\">Mobile Web (M2)</a>",
"retweeted": false,
"coordinates": null,
"entities": {
"symbols": [],
"user_mentions": [
{
"id": 183093247,
"indices": [
0,
11
],
"id_str": "183093247",
"screen_name": "HomeShop18",
"name": "HomeShop18"
}
],
"hashtags": [
{
"indices": [
12,
21
],
"text": "DreamJob"
}
],
"urls": []
},
"in_reply_to_screen_name": "HomeShop18",
"id_str": "421584490452893696",
"retweet_count": 0,
"in_reply_to_user_id": 183093247,
"favorited": false,
"user": {
"follow_request_sent": null,
"profile_use_background_image": true,
"default_profile_image": false,
"id": 2254546045,
"verified": false,
"profile_image_url_https": "https://pbs.twimg.com/profile_images/413952088880594944/rcdr59OY_normal.jpeg",
"profile_sidebar_fill_color": "171106",
"profile_text_color": "8A7302",
"followers_count": 87,
"profile_sidebar_border_color": "BCB302",
"id_str": "2254546045",
"profile_background_color": "0F0A02",
"listed_count": 1,
"profile_background_image_url_https": "https://abs.twimg.com/images/themes/theme1/bg.png",
"utc_offset": null,
"statuses_count": 9793,
"description": "Rafter. Rafting is what I do. Me aur mera Tablet. Technocrat of Future",
"friends_count": 231,
"location": "",
"profile_link_color": "473623",
"profile_image_url": "http://pbs.twimg.com/profile_images/413952088880594944/rcdr59OY_normal.jpeg",
"following": null,
"geo_enabled": false,
"profile_banner_url": "https://pbs.twimg.com/profile_banners/2254546045/1388065343",
"profile_background_image_url": "http://abs.twimg.com/images/themes/theme1/bg.png",
"name": "Jayy",
"lang": "en",
"profile_background_tile": false,
"favourites_count": 41,
"screen_name": "JzayyPsingh",
"notifications": null,
"url": null,
"created_at": "Fri Dec 20 05:46:00 +0000 2013",
"contributors_enabled": false,
"time_zone": null,
"protected": false,
"default_profile": false,
"is_translator": false
},
"geo": null,
"in_reply_to_user_id_str": "183093247",
"lang": "en",
"created_at": "Fri Jan 10 10:09:09 +0000 2014",
"filter_level": "medium",
"in_reply_to_status_id_str": null,
"place": null
}
fal*_*tru 130
正如您在下面的示例中所看到的,json.loads(和json.load)不会解码多个json对象.
>>> json.loads('{}')
{}
>>> json.loads('{}{}') # == json.loads(json.dumps({}) + json.dumps({}))
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "C:\Python27\lib\json\__init__.py", line 338, in loads
return _default_decoder.decode(s)
File "C:\Python27\lib\json\decoder.py", line 368, in decode
raise ValueError(errmsg("Extra data", s, end, len(s)))
ValueError: Extra data: line 1 column 3 - line 1 column 5 (char 2 - 4)
如果要转储多个字典,将它们包装在列表中,请转储列表(而不是多次转储字典)
>>> dict1 = {}
>>> dict2 = {}
>>> json.dumps([dict1, dict2])
'[{}, {}]'
>>> json.loads(json.dumps([dict1, dict2]))
[{}, {}]
Ada*_*hes 76
我是否可以建议您不必将所有推文打包到列表中然后执行json.dumps.您可以随时写入文件,然后使用以下命令加载它们:
tweets = []
for line in open('tweets.json', 'r'):
tweets.append(json.loads(line))
这样您就不必存储中间python对象.只要你每次append()通话写一个完整的推文,这应该有效.
Nic*_*aro 25
我遇到这个是因为我试图加载从MongoDB转储的JSON文件.它给了我一个错误
JSONDecodeError: Extra data: line 2 column 1
MongoDB JSON转储每行有一个对象,所以对我有用的是:
import json
data = []
with open('data.json') as f:
for line in f:
data.append(json.loads(line))
VIS*_*SQL 11
如果您的JSON文件不仅仅是1个JSON记录,也可能发生这种情况.JSON记录如下所示:
[{"some data": value, "next key": "another value"}]
它用括号[]打开和关闭,括号内是大括号{}.可以有很多对括号,但它们都以一个紧密的括号结束.如果您的json文件包含多个:
[{"some data": value, "next key": "another value"}]
[{"2nd record data": value, "2nd record key": "another value"}]
然后loads()将失败.
我用我自己的文件验证了这个失败.
import json
guestFile = open("1_guests.json",'r')
guestData = guestFile.read()
guestFile.close()
gdfJson = json.loads(guestData)
这是有效的,因为1_guests.json有一个记录[].我使用all_guests.json的原始文件有6条用换行符分隔的记录.我删除了5条记录(我已经通过括号检查了这些记录)并以新名称保存了该文件.然后load语句工作.
错误是
raise ValueError(errmsg("Extra data", s, end, len(s)))
ValueError: Extra data: line 2 column 1 - line 10 column 1 (char 261900 - 6964758)
PS.我使用单词record,但这不是官方名称.此外,如果你的文件有像我一样的换行符,你可以循环遍历它,将一条记录一次加载到一个json变量中.
嗯，它可能会帮助某人。当我的 json 文件是这样的时，我遇到了同样的错误
{"id":"1101010","city_id":"1101","name":"TEUPAH SELATAN"}
{"id":"1101020","city_id":"1101","name":"SIMEULUE TIMUR"}
我发现它格式不正确，所以我把它改成了某种
{
"datas":[
{"id":"1101010","city_id":"1101","name":"TEUPAH SELATAN"},
{"id":"1101020","city_id":"1101","name":"SIMEULUE TIMUR"}
]
}
如果你想在两行中解决它，你可以这样做：
with open('data.json') as f:
data = [json.loads(line) for line in f]
一线解决您的问题：
data = [json.loads(line) for line in open('tweets.json', 'r')]
小智 5
我认为将字典保存在列表中并不是@falsetru 提出的理想解决方案。
更好的方法是，迭代字典并通过添加新行将它们保存到 .json。
我们的两本词典是
d1 = {'a':1}
d2 = {'b':2}
你可以将它们写入 .json
import json
with open('sample.json','a') as sample:
for dict in [d1,d2]:
sample.write('{}\n'.format(json.dumps(dict)))
并且您可以毫无问题地读取 json 文件
with open('sample.json','r') as sample:
for line in sample:
line = json.loads(line.strip())
简单高效
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