use*_*938 2 variables shell if-statement
在 shell 程序中,我想在 if 语句中定义一个月份变量,如下所示。但我似乎无法在 if 语句中定义变量 - 我不断收到一条错误消息,提示“未找到命令 'dmonth'”。任何帮助都感激不尽!
#Enter date:
echo "Enter close-out date of MONTHLY data (in the form mmdd): "
read usedate
echo " "
#Extract first two digits of "usedate" to get the month number:
dmonthn=${usedate:0:2}
echo "month number = ${dmonthn}"
echo " "
#Translate the numeric month identifier into first three letters of month:
if [ "$dmonthn" == "01" ]; then
dmonth = 'Jan'
elif [ "$dmonthn" == "02" ]; then
dmonth = "Feb"
elif [ "$dmonthn" == "03" ]; then
dmonth = "Mar"
elif [ "$dmonthn" == "04" ]; then
dmonth = "Apr"
elif [ "$dmonthn" == "05" ]; then
dmonth = "May"
elif [ "$dmonthn" == "06" ]; then
dmonth = "Jun"
elif [ "$dmonthn" == "07" ]; then
dmonth = "Jul"
elif [ "$dmonthn" == "08" ]; then
dmonth = "Aug"
elif [ "$dmonthn" == "09" ]; then
dmonth = "Sep"
elif [ "$dmonthn" == "10" ]; then
dmonth = "Oct"
elif [ "$dmonthn" == "11" ]; then
dmonth = "Nov"
else
dmonth = "Dec"
fi
echo dmonth
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我认为你在处理空格方面遇到了麻烦......它在 Bourne shell 及其衍生中很重要。dmonth="Dec"是一个赋值,其中dmonth = "Dec"是一个以 '=' 和 'Dec' 作为参数的命令。