Ren*_*olo 5 api post json cakephp outbound
我需要发送这个:
POST http://api.outbound.io/api/v1/identify
Content-Type: application/json
{
"api_key": "MY_API_KEY",
"user_id": "MY_UNIQUE_USER_ID",
"traits" : {
"email" : "dhruv@outbound.io",
"name" : "Dhruv Mehta",
"phone" : "650xxxyyyyy"
}
}
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我从来没有做过这样的事情,我做了很多研究,但我找不到如何将这些参数发送到该URL
我希望你们能帮助我一个例子,最好的问候!
Ren*_*olo 20
经过大量的研究,我发现了如何做到......
1.-使用
App::uses('HttpSocket', 'Network/Http'); // you should put this on your controller
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2.-这是你的功能
$HttpSocket = new HttpSocket();
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3.-这里是你要通过POST发送的数据(在这个例子中,我将使用我使用的变量..你可以替换它们,添加更多或删除一些......这取决于你想要发送的信息)
$data = array(
"api_key" => "API KEY",
"user_id" => $idUser,
"event" => "other",
"extra" => array(
"course" => $course,
"price"=> $price )
);
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3.-设置标题
$request = array(
'header' => array('Content-Type' => 'application/json',
),
);
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4.-json_encode它
$data = json_encode($data);
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5.-你在哪里发送Post To?,哪个数据?,请求的类型?,这样做
$response = $HttpSocket->post('http://api.yourweburl.com/api/', $data, $request);
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*.-您可以看到取消注释此代码段的响应
//pr($response->body());
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*.-最后,如果你想在一切都完成后重定向某个地方......这样做......
$this->redirect(array('action' => 'index'));
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你应该有这样的东西.
public function actiontooutbound($idUser, $course, $price){
$HttpSocket = new HttpSocket();
$data = array(
"api_key" => "API KEY",
"user_id" => $idUser,
"event" => "other",
"extra" => array(
"course" => $course,
"price"=> $price )
);
$request = array(
'header' => array(
'Content-Type' => 'application/json',
),
);
$data = json_encode($data);
$response = $HttpSocket->post('http://api.outbound.io/api/v1/track', $data, $request);
// pr($data);
//pr($response->body());
$this->redirect(array('action' => 'index'));
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}
这是你从另一个函数调用这个函数的方法(以防万一)
$this->actiontooutbound($idUser, $course, $price);
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如果您有任何问题,现在让我很乐意为您提供帮助;)
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