Python在numpy中通过2D数组进行枚举

Question

我想要一个行为类似的函数enumerate,但是在numpy数组上.

>>> list(enumerate("hello"))
[(0, "h"), (1, "e"), (2, "l"), (3, "l"), (4, "o")]

>>> for x, y, element in enumerate2(numpy.array([[i for i in "egg"] for j in range(3)])):
        print(x, y, element)

0 0 e
1 0 g
2 0 g
0 1 e
1 1 g
2 1 g
0 2 e
1 2 g
2 2 g

目前我正在使用此功能:

def enumerate2(np_array):
    for y, row in enumerate(np_array):
        for x, element in enumerate(row):
            yield (x, y, element)

有没有更好的方法来做到这一点？例如内置函数(我找不到任何内容),或者以某种方式更快的不同定义.

Answer 1

你想要np.ndenumerate:

>>> for (x, y), element in np.ndenumerate(np.array([[i for i in "egg"] for j in range(3)])):
...     print(x, y, element)
... 
(0L, 0L, 'e')
(0L, 1L, 'g')
(0L, 2L, 'g')
(1L, 0L, 'e')
(1L, 1L, 'g')
(1L, 2L, 'g')
(2L, 0L, 'e')
(2L, 1L, 'g')
(2L, 2L, 'g')