rat*_*tio 5 c sockets linux networking tun
问题是有关要利用Tun / Tap模块的Linux主机的正确配置。
我的目标:
利用现有的路由软件(以下简称APP1和APP2),但截取和修改由它发送和接收的所有消息(由Mediator完成)。
我的场景:
Ubuntu 10.04 Machine
+---------------------------------------------+
| |
|APP1 --- tap1 --- Mediator --- tap2 --- APP2 |
| |
+---------------------------------------------+
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tap1和tap2:分别设置带有IFF_TAP标志和IP 10.0.0.1/24和10.0.0.2/24的设备设置。创建设备的代码如下:
#include <stdlib.h>
#include <stdio.h>
#include <sys/socket.h>
#include <sys/ioctl.h>
#include <fcntl.h>
#include <linux/if.h>
#include <linux/if_tun.h>
#include <string.h>
#include <errno.h>
#include <sys/resource.h>
void createTun(char *, char *, short);
int main(void)
{
const short FLAGS = IFF_TAP;
char *tunName;
char *tunIP;
// Create tap1
tunName = "tap1\0";
tunIP = "10.0.0.1/24\0";
createTun(tunName, tunIP, FLAGS);
printf("Created %s with IP %s\n", tunName, tunIP);
// Create tap2
tunName = "tap2\0";
tunIP = "10.0.0.2/24\0";
createTun(tunName, tunIP, FLAGS);
printf("Created %s with IP %s\n", tunName, tunIP);
return 0;
}
void createTun(char *tunName, char *tunIP, short FLAGS)
{
char *cmd;
char *cloneDev = "/dev/net/tun";
char *cmdIPLinkUpTemplate = "ip link set %s up";
char *cmdIPAddrAddTemplate = "ip addr add %s dev %s";
int cmdIPLinkUpRawLength = strlen(cmdIPLinkUpTemplate) - 2;
int cmdIPAddrAddRawLength = strlen(cmdIPAddrAddTemplate) - 4;
FILE *fp;
int fd, err, owner, group;
struct ifreq ifr;
owner = geteuid();
group = getegid();
// open the clone device
if((fd = open(cloneDev, O_RDWR)) < 0)
{
perror("OPEN CLONEDEV failed.");
exit(EXIT_FAILURE);
}
memset(&ifr, 0, sizeof(struct ifreq));
ifr.ifr_flags = FLAGS;
strncpy(ifr.ifr_name, tunName, strlen(tunName));
// create the device
if(ioctl(fd, TUNSETIFF, (void *) &ifr) < 0)
{
perror("IOCTL SETIFF denied.");
close(fd);
exit(EXIT_FAILURE);
}
// set dev owner
if(owner != -1)
{
if(ioctl(fd, TUNSETOWNER, owner) < 0)
{
perror("IOCTL SETOWNER denied.");
close(fd);
exit(EXIT_FAILURE);
}
}
// set dev group
if(group != -1)
{
if(ioctl(fd, TUNSETGROUP, group) < 0)
{
perror("IOCTL SETGROUP denied.");
close(fd);
exit(EXIT_FAILURE);
}
}
// set dev persistent
if(ioctl(fd, TUNSETPERSIST, 1) < 0)
{
perror("IOCTL SETPERSIST denied.");
close(fd);
exit(EXIT_FAILURE);
}
// Set dev up
cmd = malloc(cmdIPLinkUpRawLength + strlen(tunName) + 1);
sprintf(cmd, cmdIPLinkUpTemplate, ifr.ifr_name);
fp = popen(cmd, "r");
if(fp == NULL)
{
perror("POPEN failed.");
close(fd);
free(cmd);
exit(EXIT_FAILURE);
}
pclose(fp);
free(cmd);
// Assign IP
cmd = malloc(cmdIPAddrAddRawLength + strlen(tunIP) + strlen(tunName) + 1);
sprintf(cmd, cmdIPAddrAddTemplate, tunIP, tunName);
fp = popen(cmd, "r");
if(fp == NULL)
{
perror("POPEN failed.");
close(fd);
free(cmd);
exit(EXIT_FAILURE);
}
pclose(fp);
free(cmd);
return;
}
Run Code Online (Sandbox Code Playgroud)介体:小的自编写代码,可以在tap1和tap2之间简单地中继数据。基本结构如下:
#include <unistd.h>
#include <stdio.h>
#include <sys/socket.h>
#include <netinet/ip.h>
#include <sys/ioctl.h>
#include <sys/resource.h>
#include <sys/epoll.h>
#include <errno.h>
#include <fcntl.h>
#include <stdlib.h>
#include <string.h>
#include <linux/if.h>
#include <linux/if_tun.h>
int main(int argc, char *argv[])
{
const int NOF_FD = 2;
const char *TUN1 = "tap1";
const char *TUN2 = "tap2";
const char *CLONEDEV = "/dev/net/tun";
int fd_tun1, fd_tun2, fd_epoll;
struct ifreq ifr_tun1, ifr_tun2;
struct epoll_event ev;
const int MAX_EVENTS = 1;
int ready, s, t;
const int MAX_BUF = 2000;
char buf[MAX_BUF];
struct sockaddr_in to;
const short FLAGS = IFF_TAP;
// Open tap1
if((fd_tun1 = open(CLONEDEV, O_RDWR)) < 0)
{
perror("OPEN CLONEDEV for tun1 failed");
exit(EXIT_FAILURE);
}
memset(&ifr_tun1, 0, sizeof(struct ifreq));
ifr_tun1.ifr_flags = FLAGS;
strcpy(ifr_tun1.ifr_name, TUN1);
if(ioctl(fd_tun1, TUNSETIFF, (void *) &ifr_tun1) < 0)
{
perror("IOCTL SETIFF for tap1 failed");
close(fd_tun1);
exit(EXIT_FAILURE);
}
// Open tap2
if((fd_tun2 = open(CLONEDEV, O_RDWR)) < 0)
{
perror("OPEN CLONEDEV for tap2 failed");
exit(EXIT_FAILURE);
}
memset(&ifr_tun2, 0, sizeof(struct ifreq));
ifr_tun2.ifr_flags = FLAGS;
strcpy(ifr_tun2.ifr_name, TUN2);
if(ioctl(fd_tun2, TUNSETIFF, (void *) &ifr_tun2) < 0)
{
perror("IOCTL SETIFF for tun2 failed");
close(fd_tun1);
close(fd_tun2);
exit(EXIT_FAILURE);
}
// Prepare EPOLL
if((fd_epoll = epoll_create(NOF_FD)) < 0)
{
perror("EPOLL CREATE failed");
close(fd_tun1);
close(fd_tun2);
exit(EXIT_FAILURE);
}
memset(&ev, 0, sizeof(ev));
ev.events = EPOLLIN;
ev.data.fd = fd_tun1;
if(epoll_ctl(fd_epoll, EPOLL_CTL_ADD, fd_tun1, &ev) < 0)
{
perror("EPOLL CTL ADD fd_tun1 failed");
close(fd_tun1);
close(fd_tun2);
close(fd_epoll);
exit(EXIT_FAILURE);
}
memset(&ev, 0, sizeof(ev));
ev.events = EPOLLIN;
ev.data.fd = fd_tun2;
if(epoll_ctl(fd_epoll, EPOLL_CTL_ADD, fd_tun2, &ev) < 0)
{
perror("EPOLL CTL ADD fd_tun2 failed");
close(fd_tun1);
close(fd_tun2);
close(fd_epoll);
exit(EXIT_FAILURE);
}
// Do relay
while(1)
{
if((ready = epoll_wait(fd_epoll, &ev, MAX_EVENTS, -1)) < 0)
{
if(errno == EINTR)
continue;
else
{
perror("EPOLL WAIT failed");
close(fd_tun1);
close(fd_tun2);
close(fd_epoll);
exit(EXIT_FAILURE);
}
}
//printf("EPOLL WAIT SIGNALED\n");
if(ev.events & EPOLLIN)
{
if((s = read(ev.data.fd, buf, MAX_BUF)) < 0)
{
perror("READ failed");
close(fd_tun1);
close(fd_tun2);
close(fd_epoll);
exit(EXIT_FAILURE);
}
printf("Read from %s. Bytes: %d\nData:\n", (ev.data.fd == fd_tun1 ? "tun1" : "tun2"), s);
int k;
for(k = 0; k < s; k++)
{
printf("%c", buf[k]);
}
printf("\n");
t = (ev.data.fd == fd_tun1) ? fd_tun2 : fd_tun1;
if((s = write(t, buf, s)) < 0)
{
perror("WRITE failed");
close(fd_tun1);
close(fd_tun2);
close(fd_epoll);
exit(EXIT_FAILURE);
}
printf("Written to %s. Bytes: %d\n", (t == fd_tun1 ? "tun1" : "tun2"), s);
if(epoll_ctl(fd_epoll, EPOLL_CTL_DEL, ev.data.fd, NULL) < 0)
{
perror("EPOLL CTL DEL failed");
close(fd_tun1);
close(fd_tun2);
close(fd_epoll);
exit(EXIT_FAILURE);
}
if(epoll_ctl(fd_epoll, EPOLL_CTL_ADD, ev.data.fd, &ev) < 0)
{
perror("EPOLL CTL ADD failed");
close(fd_tun1);
close(fd_tun2);
close(fd_epoll);
exit(EXIT_FAILURE);
}
}
printf("\n\n");
}
}
Run Code Online (Sandbox Code Playgroud)APP1和APP2:OSPF路由守护程序分别通过tap1和tap2进行通信。守护程序的痕迹表明,基本上涉及以下系统调用:
socket(PF_INET, SOCK_RAW, 0X59 /*IPPROTO_??? */) = 8 // Opening a socket for OSPF and tap1
fcntl64(8, F_SETFL, 0_RDONLY | 0_NONBLOCK) = 0
setsockopt(8, SOL_IP, IP_TOS, [192], 4) = 0
setsockopt(8, SOL_SOCKET, SO_PRIORITY, [7], 4) = 0
setsockopt(8, SOL_IP, IP_PKTINFO, [1], 4) = 0
setsockopt(8, SOL_IP, IP_MTU_DISCOVER, [0], 4) = 0
setsockopt(8, SOL_IP, IP_MULTICAST_LOOP, [0], 4) = 0
setsockopt(8, SOL_IP, IP_MULTICAST_TTL, [1], 4) = 0
setsockopt(8, SOL_IP, IP_MUTLICAST_IF, "\0\0\0\0\n\0\0\1\223\0\0\0", 12) = 0
setsockopt(8, SOL_SOCKET, SO_BINDTODEVICE, "tap1\0\0\0\0\0\0\0\0\0\0\0\0\0\315\375\307\250\352\t\t8\207\t\10\0\0\0\0", 32) = 0
setsockopt(8, SOL_IP, IP_ADD_MEMBERSHIP, "340\0\0\5\n\0\0\1\223\0\0\0", 12) = 0
// Then it gets in a cycle like:
select(9, [3, 7, 8], [], NULL, {1, 0}) = 0 (Timeout)
clock_gettime(CLOCK_MONOTONIC, {120893, 360452769}) = 0
time(NULL)
clock_gettime(CLOCK_MONOTONIC, {120893, 360504525}) = 0
select(9, [3, 7, 8], [], NULL, {1, 0}) = 0 (Timeout)
clock_gettime(CLOCK_MONOTONIC, {120894, 363022746}) = 0
time(NULL)
...
Run Code Online (Sandbox Code Playgroud)我的用法:
我的问题:
即使连接到Tap1的Wireshk可以同时看到Tap1和Tap2的消息,APP2也不会接收APP1发送的消息,APP2也不会接收来自APP1的消息。在上面显示的strace提取中,select()调用从不返回文件描述符8,该文件描述符实际上是连接到tap1的套接字。
我的问题:
即使APP1发送了这些消息,并由Mediator中继并由tap1附带的Wireshark看到了,APP1为什么仍未收到APP2发送的消息?
我是否需要在Linux主机上添加任何类型/种类的其他路由?
设置调音/攻丝设备时是否出错?
我的调解员代码不能正常工作吗?
我没有尝试过你的代码(有点奇怪的是你能够从用户空间打开 TAP 设备两次而不使用多队列标志,但我们假设这是正确的),但是你处理 TAP 设备的方式有一个概念错误。
TUN/TAP 本质上只是一个管道,该管道的一侧位于内核(tapX 接口),另一侧位于某些用户空间应用程序中。该应用程序向管道写入的任何内容都会作为传入流量到达内核接口(您可以使用wireshark看到它)。无论内核发送到该管道(发送到 TapX)的内容最终都会进入应用程序(您可以在应用程序中读取的数据)。
您的代码当前所做的是打开同一管道的另一个用户空间部分,但这不是您想要的。您希望获得管道另一侧的流量。从技术上讲,您当前正在做的事情可以通过一个简单的桥接接口来完成,两个分接头都作为端口添加到其中。当然,如果您不仅想桥接,还想以某种方式修改流量,事情就会变得有点复杂。
解决此问题的一种方法是添加另一对 TAP 接口。您桥接(如在内核桥接中)您的tap1 与tap3,tap2 与tap4,现在您在“中介”中打开tap3 和tap4,并在它们之间的代理框架中打开tap3 和tap4。这效率非常低,但可能是解决您问题的方法。
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