Sil*_*rol 2 java serialization exception treemap notserializableexception
我有一个相当大的项目(大学的OOP课程):一个学校注册,学生可以看到他们的成绩,教师可以增加成绩等等.
"base"类是一个包含所有使用的类(Java)的单例,例如用户数组,类(如在学校类中)和将classess和教师关联到课程的TreeMap.
我想序列化这个基类(Central),以便保存修改后的数据.问题是我得到了这个例外
java.io.NotSerializableException: liceu.Central$1
at java.io.ObjectOutputStream.writeObject0(ObjectOutputStream.java:1183)
at java.io.ObjectOutputStream.defaultWriteFields(ObjectOutputStream.java:1547)
at java.io.ObjectOutputStream.defaultWriteObject(ObjectOutputStream.java:440)
at java.util.TreeMap.writeObject(TreeMap.java:2265)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:606)
at java.io.ObjectStreamClass.invokeWriteObject(ObjectStreamClass.java:988)
at java.io.ObjectOutputStream.writeSerialData(ObjectOutputStream.java:1495)
at java.io.ObjectOutputStream.writeOrdinaryObject(ObjectOutputStream.java:1431)
at java.io.ObjectOutputStream.writeObject0(ObjectOutputStream.java:1177)
at java.io.ObjectOutputStream.defaultWriteFields(ObjectOutputStream.java:1547)
at java.io.ObjectOutputStream.writeSerialData(ObjectOutputStream.java:1508)
at java.io.ObjectOutputStream.writeOrdinaryObject(ObjectOutputStream.java:1431)
at java.io.ObjectOutputStream.writeObject0(ObjectOutputStream.java:1177)
at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:347)
at liceu.Main.main(Main.java:31)
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我的所有类都实现了Serializable,它们没有瞬态或静态字段(单例除外,它具有实例变量和getInstance方法作为静态).
因为发布会有很多代码(我会冒着通过在提交之前发布它来使我的作业无效),我试图通过尝试隔离错误来进行概念验证.
public class Central implements Serializable
{
private ArrayList <User> users;
private ArrayList <Class> classess;
private TreeMap <Course, TreeMap <Class, Professor>> reunite;
private static Central instance = null;
private Central()
{
users = new ArrayList<>();
classess = new ArrayList<>();
reunite = new TreeMap<>(new Comparator<Student>(){
@Override
public int compare(Student e1, Student e2)
{
return e1.getName().compareTo(e2.getName());
}
});
}
}
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如果我只保留前2个ArrayLists,则序列化过程有效.问题出在TreeMap上.
TreeMap类是否可序列化?(一般情况下)是不是因为匿名比较器?
这是序列化的主类
public class Main
{
public static void main(String args[])
{
Central cent = Central.getInstance();
FileOutputStream fos;
ObjectOutputStream oos;
cent.addUser(new Student(3,"id","pass","name","surname"));
cent.addUser(new Student(3,"id2","pass","name","surname"));
cent.addUser(new Student(3,"id1","pass","name","surname"));
try
{
fos = new FileOutputStream("save.txt");
oos = new ObjectOutputStream(fos);
oos.writeObject(cent);
}
catch(IOException e)
{
e.printStackTrace();
}
}
}
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JB *_*zet 13
TreeMap保存对用于比较键的比较器的引用.比较器是一个不可序列化的匿名类的实例.所以你得到了这个例外.
将匿名比较器重构为顶级或命名内部类,它也实现Serializable.
给力的另一种方法Comparator是Serializable将它与另外结合投转换为拉姆达:
TreeMap<Integer, String> sortedMap = new TreeMap<>(
(Comparator<Integer> & Serializable) (o1, o2) -> {
return o1.compareTo(o2);
}
);
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这是解释: Java lambda 表达式、强制转换和比较器。