Laravel分页漂亮的URL

Question

有没有办法在Laravel 4中获得一个分页漂亮的URL？

例如,默认情况下:

http://example.com/something/?page=3

我想得到什么:

http://example.com/something/page/3

此外,分页应该以这种方式呈现,并且追加分页应该以这种方式出现.

Answer 1

这是一个hacky解决方法.我正在使用Laravel v4.1.23.它假定页码是您网址的最后一位.没有深入测试,所以我对人们可以找到的任何错误感兴趣.我对更好的解决方案更感兴趣:-)

路线:

Route::get('/articles/page/{page_number?}', function($page_number=1){
    $per_page = 1;
    Articles::resolveConnection()->getPaginator()->setCurrentPage($page_number);
    $articles = Articles::orderBy('created_at', 'desc')->paginate($per_page);
    return View::make('pages/articles')->with('articles', $articles);
});

视图:

<?php
    $links = $articles->links();
    $patterns = array();
    $patterns[] = '/'.$articles->getCurrentPage().'\?page=/';
    $replacements = array();
    $replacements[] = '';
    echo preg_replace($patterns, $replacements, $links);
?>

模型:

<?php
class Articles extends Eloquent {
    protected $table = 'articles';
}

移民:

<?php

use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;

class CreateArticlesTable extends Migration {

    public function up()
    {
        Schema::create('articles', function($table){
            $table->increments('id');
            $table->string('slug');
            $table->string('title');
            $table->text('body');
            $table->timestamps();
        });
    }

    public function down()
    {
        Schema::drop('articles');
    }
}

Answer 2

这是可能的,但你需要编写一些代码.

首先,您需要更改app/config/app.php分页服务提供程序 - 您需要自己编写.

评论:

// 'Illuminate\Pagination\PaginationServiceProvider',

并添加

'Providers\PaginationServiceProvider',

在提供者部分.

现在您需要创建PaginationServiceProvider以使用自定义分页工厂:

model/Providers/PaginationServiceProvider.php 文件:

<?php

namespace Providers;

use Illuminate\Support\ServiceProvider;

class PaginationServiceProvider extends ServiceProvider
{

    /**
     * Indicates if loading of the provider is deferred.
     *
     * @var bool
     */
    protected $defer = true;

    /**
     * Register the service provider.
     *
     * @return void
     */
    public function register()
    {
        $this->app->bindShared('paginator', function ($app) {
            $paginator = new PaginationFactory($app['request'], $app['view'],
                $app['translator']);

            $paginator->setViewName($app['config']['view.pagination']);

            $app->refresh('request', $paginator, 'setRequest');

            return $paginator;
        });
    }

    /**
     * Get the services provided by the provider.
     *
     * @return array
     */
    public function provides()
    {
        return array('paginator');
    }

}

在上面创建Providers\PaginationFactory对象,所以现在我们需要创建这个文件:

model/providers/PaginationFactory.php 文件:

<?php


namespace Providers;

use Illuminate\Pagination\Factory;


class PaginationFactory extends  Factory {

    /**
     * Get a new paginator instance.
     *
     * @param  array  $items
     * @param  int    $total
     * @param  int|null  $perPage
     * @return \Illuminate\Pagination\Paginator
     */
    public function make(array $items, $total, $perPage = null)
    {
        $paginator = new \Utils\Paginator($this, $items, $total, $perPage);

        return $paginator->setupPaginationContext();
    }        
} 

在这里你只创建\Utils\Paginator对象所以现在让我们创建它:

model/Utils/Paginator.php 文件:

<?php

namespace Utils;



class Paginator extends \Illuminate\Pagination\Paginator {


    /**
     * Get a URL for a given page number.
     *
     * @param  int  $page
     * @return string
     */
    public function getUrl($page)
    {
      $routeParameters = array();

      if ($page > 1) { // if $page == 1 don't add it to url
         $routeParameters[$this->factory->getPageName()] = $page;
      }

      return \URL::route($this->factory->getCurrentUrl(), $routeParameters);
    }
}

在这个文件中,我们最终覆盖了创建分页URL的默认方法.

我们假设你有这样定义的路线:

Route::get('/categories/{page?}',
    ['as'   => 'categories',
     'uses' => 'CategoryController@displayList'
    ])->where('page', '[1-9]+[0-9]*');

如你所见,我们在这里定义了路由名称as(由于上面的Paginator实现很重要 - 但你当然可以用不同的方式来实现).

现在,在方法displayList的CategoryController类,你可以这样做:

public function displayList($categories, $page = 1) // default 1 is needed here 
{
    Paginator::setCurrentPage($page);
    Paginator::setBaseUrl('categories'); // use here route name and not the url
    Paginator::setPageName('page');

    $categories = Category::paginate(15);


    return View::make('admin.category')->with(
        ['categories' => $categories]
    );
}

在您的视图中添加:

<?php echo $categories->links(); ?>

您将以这种方式获得生成的URL:

http://localhost/categories
http://localhost/categories/2
http://localhost/categories/3
http://localhost/categories/4
http://localhost/categories/5

没有？在查询字符串中

但是在我看来,默认情况下应该添加这样的东西,或者至少它应该足以扩展一个类而不是为了实现一个方法而创建3个类.