我尝试删除char*时,Debug Assertion失败

Question

我是C++新手并学习虚函数,并且知道如果类有虚函数并且类有指针成员,我们必须编写虚析构函数.下面是我的代码,我正在使用Virtual Studio 2013RC

#include<iostream>

using namespace std;
//base and derived class with virtual function
class Parent{
protected:
    const char *name;
public:
    virtual void say(){ cout << "1" << endl; }
    virtual void showName(){ cout << name << endl; }
    Parent(){};
    Parent(const char *myName) :name(myName){};
    virtual ~Parent(){ delete name; cout << "Parent name deleted" << endl; }
};

class Child :public Parent{
protected:
    const char *name;
public:
    virtual void say(){ cout << "2" << endl; }
    virtual void showName(){ cout << name << endl; }
    Child(){};
    Child(const char *myName) :name(myName){};
    virtual ~Child(){ delete name; cout << "Child name deleted" << endl;}
}; 

int main(){
    Child a("Tom");
    return 0;
}

要么

int main(){
    Parent *a = new Child("Tom");
    delete a;        
    return 0;
}

两者都会给出Debug Assertion Failed的错误窗口.

对于这种情况,我应该如何正确编写虚拟析构函数？

非常感谢

Answer 1

因为您尝试删除文字字符串指针.您将Child::name成员设置为指向文字字符串"Tom",该字符串是指向编译器创建的内存的指针.你应该只delete明确你的意思new.

另请注意,每个Parent和Child类都有不同且不同的name成员变量.初始化Child::name变量时,其中的变量Parent仍未初始化.