way*_*way 4 cocoa-touch nsarray ios uilocalnotification
有没有办法找到NSDate下一个将触发的本地通知?
例如,我设置了三个本地通知:
通知#1:设置为昨天下午3:00开始,每天重复间隔.
通知#2:今天下午5点开始点火,每天重复一次.
通知#3:明天下午6点开始,每天重复一次.
鉴于当前是下午4:00,将触发的下一个本地通知是通知#2.
如何检索此本地通知并获取其日期?
我知道我可以在一个数组中检索这些本地通知,但是如何根据今天的日期获取下一个?
Mar*_*n R 11
您的任务的主要目标是确定每个通知的给定日期之后的"下一个开火日期".a的NSLog()输出UILocalNotification显示了下一个发布日期,但遗憾的是它似乎不能用作(公共)属性.
我从/sf/answers/1311131461/(经过小改进)中获取了代码并将其重写为类别方法UILocalNotification.(这不完美.它不包括已为通知分配时区的情况.)
@interface UILocalNotification (MyNextFireDate)
- (NSDate *)myNextFireDateAfterDate:(NSDate *)afterDate;
@end
@implementation UILocalNotification (MyNextFireDate)
- (NSDate *)myNextFireDateAfterDate:(NSDate *)afterDate
{
// Check if fire date is in the future:
if ([self.fireDate compare:afterDate] == NSOrderedDescending)
return self.fireDate;
// The notification can have its own calendar, but the default is the current calendar:
NSCalendar *cal = self.repeatCalendar;
if (cal == nil)
cal = [NSCalendar currentCalendar];
// Number of repeat intervals between fire date and the reference date:
NSDateComponents *difference = [cal components:self.repeatInterval
fromDate:self.fireDate
toDate:afterDate
options:0];
// Add this number of repeat intervals to the initial fire date:
NSDate *nextFireDate = [cal dateByAddingComponents:difference
toDate:self.fireDate
options:0];
// If necessary, add one more:
if ([nextFireDate compare:afterDate] == NSOrderedAscending) {
switch (self.repeatInterval) {
case NSDayCalendarUnit:
difference.day++;
break;
case NSHourCalendarUnit:
difference.hour++;
break;
// ... add cases for other repeat intervals ...
default:
break;
}
nextFireDate = [cal dateByAddingComponents:difference
toDate:self.fireDate
options:0];
}
return nextFireDate;
}
@end
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使用它,您可以根据下一个开火日期对一组本地通知进行排序:
NSArray *notifications = @[notif1, notif2, notif3];
NSDate *now = [NSDate date];
NSArray *sorted = [notifications sortedArrayUsingComparator:^NSComparisonResult(UILocalNotification *obj1, UILocalNotification *obj2) {
NSDate *next1 = [obj1 myNextFireDateAfterDate:now];
NSDate *next2 = [obj2 myNextFireDateAfterDate:now];
return [next1 compare:next2];
}];
Run Code Online (Sandbox Code Playgroud)
现在sorted[0]将是下一个触发的通知.