如何mysqli_real_escape_string在我的脚本中使用以防止SQL注入.我正在研究一些代码并在这里提出一些问题而且我被建议使用mysqli_real_escape_string而不是mysql_real_escape_string,问题是我的代码在我想要保护的变量之后才建立连接.有人建议我应该使用预备语句,但经过一些搜索http://www.php.net/manual/en/mysqli.quickstart.prepared-statements.php后,我感到更加困惑.现在代码如果完全做了它不应该做的事情,它将空值/行插入到我的表中,从我的阅读中可能是因为使用了mysqli_real_escaape_string
任何想法或帮助都表示赞赏,我很沮丧和困惑但仍在努力学习.这是代码:
<?php
//Form fields passed to variables
$manu = mysqli_real_escape_string($_POST['inputManu']);
$model = mysqli_real_escape_string($_POST['inputModel']);
$desc = mysqli_real_escape_string($_POST['inputDesc']);
//Connect to database using $conn
include ('connection.php');
//Insert record into table
$sql = "INSERT INTO gear (`id`,`manu`,`model`,`desc`)
VALUES (NULL,'$manu','$model','$desc')";
//Check for empty fields
if (isset($_POST['submit']))
{
foreach($_POST as $val)
{
if(trim($val) == '' || empty($val))
{
die('Error: ' . mysqli_error());
echo "Please complete all form fields!";
echo "<meta http-equiv='Refresh' content='3; URL=../add.php'>";
}
}
if (!mysqli_query($conn,$sql))
{
die('Error: ' . mysqli_error($conn));
}
else
{
//echo "1 record added";
echo "Success, You added the ".$manu." ".$model."";
echo "<meta http-equiv='Refresh' content='3; URL=../index.php'>";
}
}
else
{
echo "some error";
}
mysqli_close($conn);
?>
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<?php
//Connect to database using $conn
include ('connection.php');
//Form fields passed to variables
$manu = mysqli_real_escape_string($conn, $_POST['inputManu']);
$model = mysqli_real_escape_string($conn, $_POST['inputModel']);
$desc = mysqli_real_escape_string($conn, $_POST['inputDesc']);
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