从嵌套的JSON对象中检索值

Question

我有JSON文件,我想解析.JSON文件("myfile")的格式如下:

{
    "LanguageLevels": {
        "1": "Pocz?tkuj?cy",
        "2": "?rednioZaawansowany",
        "3": "Zaawansowany",
        "4": "Ekspert"
    }
}

我想从语言级别中检索Key 2的值(ŚrednioZaawansowany).

import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.Iterator;
import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
import org.json.simple.parser.ParseException;

public class JsonSimpleExample {
public static void main(String[] args) {

JSONParser parser = new JSONParser();

try {

    Object obj = parser.parse(new FileReader("myfile"); 
    JSONObject jsonObject = (JSONObject) obj;
    JSONObject jsonChildObject = (JSONObject)jsonObject.get("LanguageLevels");

接下来做什么？我如何迭代它？

Answer 1

也许您没有使用最新版本的JSON for Java Library.

json-simple还没有更新很长一段时间,而是在JSON-Java2个月前更新.

JSON-Java可以在GitHub上找到,这里是它的回购链接:https://github.com/douglascrockford/JSON-java

切换库后,您可以参考下面的示例代码:

public static void main(String[] args) {
    String JSON = "{\"LanguageLevels\":{\"1\":\"Pocz\\u0105tkuj\\u0105cy\",\"2\":\"\\u015arednioZaawansowany\",\"3\":\"Zaawansowany\",\"4\":\"Ekspert\"}}\n";

    JSONObject jsonObject = new JSONObject(JSON);
    JSONObject getSth = jsonObject.getJSONObject("LanguageLevels");
    Object level = getSth.get("2");

    System.out.println(level);
}

作为JSON-Java开源的,您可以阅读代码及其文档,它们将指导您完成.

希望它有所帮助.

Answer 2

您必须逐步迭代到嵌套的 JSON 中。

例如从 Google 地理编码 api 收到的 JSON

{
   "results" : [
      {
         "address_components" : [
            {
               "long_name" : "Bhopal",
               "short_name" : "Bhopal",
               "types" : [ "locality", "political" ]
            },
            {
               "long_name" : "Bhopal",
               "short_name" : "Bhopal",
               "types" : [ "administrative_area_level_2", "political" ]
            },
            {
               "long_name" : "Madhya Pradesh",
               "short_name" : "MP",
               "types" : [ "administrative_area_level_1", "political" ]
            },
            {
               "long_name" : "India",
               "short_name" : "IN",
               "types" : [ "country", "political" ]
            }
         ],
         "formatted_address" : "Bhopal, Madhya Pradesh, India",
         "geometry" : {
            "bounds" : {
               "northeast" : {
                  "lat" : 23.3326697,
                  "lng" : 77.5748062
               },
               "southwest" : {
                  "lat" : 23.0661497,
                  "lng" : 77.2369767
               }
            },
            "location" : {
               "lat" : 23.2599333,
               "lng" : 77.412615
            },
            "location_type" : "APPROXIMATE",
            "viewport" : {
               "northeast" : {
                  "lat" : 23.3326697,
                  "lng" : 77.5748062
               },
               "southwest" : {
                  "lat" : 23.0661497,
                  "lng" : 77.2369767
               }
            }
         },
         "place_id" : "ChIJvY_Wj49CfDkR-NRy1RZXFQI",
         "types" : [ "locality", "political" ]
      }
   ],
   "status" : "OK"
}

我将以下面给定的方式迭代 到 "location" : { "lat" : 23.2599333, "lng" : 77.412615

//在json对象中接收JSON

        JSONObject json = new JSONObject(output.toString());
        JSONArray result = json.getJSONArray("results");
        JSONObject result1 = result.getJSONObject(0);
        JSONObject geometry = result1.getJSONObject("geometry");
        JSONObject locat = geometry.getJSONObject("location");

        //"iterate onto level of location";

        double lat = locat.getDouble("lat");
        double lng = locat.getDouble("lng");

Answer 3

你可以看到JSONObject扩展了一个HashMap,所以你可以简单地将它用作HashMap:

JSONObject jsonChildObject = (JSONObject)jsonObject.get("LanguageLevels");
for (Map.Entry in jsonChildOBject.entrySet()) {
    System.out.println("Key = " + entry.getKey() + ", Value = " + entry.getValue());
}