Sco*_*ott 8 java xml json moxy
我正在使用MOXy和Jersey实现一个RESTful API,并希望自然地为JSON和XML返回列表,我的意思是XML包含整个集合的元素标记以及集合项,而JSON包含仅用于集合的标记.
例如,我想返回一个"组织"资源,其中包含设施和位置的嵌套列表.作为XML:
<organisation>
<id>1</id>
<name>XYZ</name>
<facilities>
<facility>
<id>1</id>
<text>Telephone</text>
</facility>
<facility>
<id>3</id>
<text>Whiteboard</text>
</facility>
</facilities>
<locations>
<location>
<id>1</id>
<kind>REGION</kind>
<name>London</name>
</location>
<location>
<id>2</id>
<kind>REGION</kind>
<name>Manchester</name>
</location>
</locations>
</organisation>
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而作为JSON:
{
"id": 1,
"name": "XYZ",
"facilities": [
{
"id": 1,
"text": "Telephone"
},
{
"id": 3,
"text": "Whiteboard"
}
],
"locations": [
{
"id": 1,
"kind": "REGION",
"name": "London"
},
{
"id": 2,
"kind": "REGION",
"name": "Manchester"
}
]
}
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不幸的是,我似乎无法获得允许我为XML和JSON返回这样的输出的代码库.如果我使用一个类来包装嵌套列表,那么XML看起来是正确的但不是JSON(参见下面的"ExternalFacilities").如果我将嵌套列表定义为ArrayList
子类,则JSON显示正确但不是XML(请参阅下面的"ExternalLocations").
XML示例显示"设施"列表正确但不是"位置"
看到没有包含"位置"列表的XML元素(就像"设施"一样),并且每个位置都有一个复数元素名称.
<organisation>
<id>1</id>
<name>XYZ</name>
<facilities>
<facility>
<id>1</id>
<text>Telephone</text>
</facility>
<facility>
<id>3</id>
<text>Whiteboard</text>
</facility>
</facilities>
<locations>
<id>1</id>
<kind>REGION</kind>
<name>London</name>
</locations>
<locations>
<id>2</id>
<kind>REGION</kind>
<name>Manchester</name>
</locations>
</organisation>
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JSON样本显示"位置"列表正确但不是"设施"
看到"facility"列表是一个包含JSON数组的JSON对象,而我只想要JSON数组(带有复数元素名称).
{
"id": 1,
"name": "XYZ",
"facilities": {
"facility": [
{
"id": 1,
"text": "Telephone"
},
{
"id": 3,
"text": "Whiteboard"
}
]
},
"locations": [
{
"id": 1,
"kind": "REGION",
"name": "London"
},
{
"id": 2,
"kind": "REGION",
"name": "Manchester"
}
]
}
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上面的示例使用相同的代码生成,只需更改Accept HTTP标头以使Jersey返回JSON而不是XML.以下是课程的摘录:
ExternalOrganisation.java
@XmlRootElement(name="organisation")
@XmlAccessorType(XmlAccessType.FIELD)
public class ExternalOrganisation {
private String name;
private ExternalFacilities facilities;
private ExternalLocations locations;
...
}
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ExternalFacilities.java
@XmlRootElement(name="facilities")
public class ExternalFacilities {
@XmlElementRef
private List<ExternalFacility> list;
...
}
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ExternalLocations.java
@XmlRootElement(name="locations")
public class ExternalLocations extends ArrayList<ExternalLocation> {
...
}
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ExternalFacility.java
@XmlRootElement(name="facility")
@XmlType(propOrder={"id", "uri", "kind", "text"})
public class ExternalFacility extends ExternalBase {
// id inherited
private String text;
....
}
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ExternalLocation.java
@XmlRootElement(name="location")
@XmlType(propOrder={"id", "kind", "name"})
public class ExternalLocation extends ExternalBase {
// id inherited
@XmlElement private LocationKind kind;
@XmlElement private String name;
...
}
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似乎最初类似于这个问题,但我不是想在我的列表中混合对象的类型.
您可以执行以下操作来获取所需的 XML 和 JSON 表示形式:
@XMLElementWrapper
代替:
@XmlRootElement(name="organisation")
@XmlAccessorType(XmlAccessType.FIELD)
public class ExternalOrganisation {
private String name;
private ExternalFacilities facilities;
private ExternalLocations locations;
...
}
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您可以执行以下操作@XmlElementWrapper
(请参阅: http://blog.bdoughan.com/2010/09/jaxb-collection-properties.html):
@XmlRootElement(name="organisation")
@XmlAccessorType(XmlAccessType.FIELD)
public class ExternalOrganisation {
private String name;
@XmlElementWrapper
@XmlElementRef
private List<ExternalFacility> facilities;
@XmlElementWrapper
@XmlElementRef
private List<ExternalLocation> locations;
...
}
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通过将包装器指定为数组名称属性,MOXy 将使用来自的值@XmlElementWrapper
作为 JSON 数组名称。
import java.util.*;
import javax.ws.rs.core.Application;
import org.eclipse.persistence.jaxb.rs.MOXyJsonProvider;
public class YourApplication extends Application {
@Override
public Set<Class<?>> getClasses() {
HashSet<Class<?>> set = new HashSet<Class<?>>(1);
set.add(YourService.class);
return set;
}
@Override
public Set<Object> getSingletons() {
MOXyJsonProvider moxyJsonProvider = new MOXyJsonProvider();
moxyJsonProvider.setWrapperAsArrayName(true);
HashSet<Object> set = new HashSet<Object>(1);
set.add(moxyJsonProvider);
return set;
}
}
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