Igo*_* R. 4 memory-management virtual-memory linux-kernel
在内核模块(2.6.32-358.el6.x86_64)中,我想打印出所有映射到进程虚拟内存的物理地址。鉴于task->mm,我尝试struct page按如下方式遍历该过程:
int i, j, k, l;
for (i = 0; i < PTRS_PER_PGD; ++i)
{
pgd_t *pgd = mm->pgd + i;
if (pgd_none(*pgd) || pgd_bad(*pgd))
continue;
for (j = 0; j < PTRS_PER_PUD; ++j)
{
pud_t *pud = (pud_t *)pgd_page_vaddr(*pgd) + j;
if (pud_none(*pud) || pud_bad(*pud))
continue;
for (k = 0; k < PTRS_PER_PMD; ++k)
{
pmd_t *pmd = (pmd_t *)pud_page_vaddr(*pud) + k;
if (pmd_none(*pmd) || pmd_bad(*pmd))
continue;
for (l = 0; l < PTRS_PER_PTE; ++l)
{
pte_t *pte = (pte_t *)pmd_page_vaddr(*pmd) + l;
if (!pte || pte_none(*pte))
continue;
struct page *p = pte_page(*pte);
unsigned long phys = page_to_phys(p);
printk(KERN_NOTICE "addr %lx", phys);
}
}
}
}
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输出看起来有点奇怪(特别是有一系列相同的地址),所以我想问一下,理论上上述是否正确。
更好的方法是遍历进程的 VMA 并通过页目录将每个 VMA 转换为物理页/地址:
struct vm_area_struct *vma = 0;
unsigned long vpage;
if (task->mm && task->mm->mmap)
for (vma = task->mm->mmap; vma; vma = vma->vm_next)
for (vpage = vma->vm_start; vpage < vma->vm_end; vpage += PAGE_SIZE)
unsigned long phys = virt2phys(task->mm, vpage);
//...
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哪里virt2phys看起来像这样:
//...
pgd_t *pgd = pgd_offset(mm, virt);
if (pgd_none(*pgd) || pgd_bad(*pgd))
return 0;
pud = pud_offset(pgd, virt);
if (pud_none(*pud) || pud_bad(*pud))
return 0;
pmd = pmd_offset(pud, virt);
if (pmd_none(*pmd) || pmd_bad(*pmd))
return 0;
if (!(pte = pte_offset_map(pmd, virt)))
return 0;
if (!(page = pte_page(*pte)))
return 0;
phys = page_to_phys(page);
pte_unmap(pte);
return phys;
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