Zac*_*ing 11 python encryption file aes pycrypto
我已经有了一个工作程序,但唯一不起作用的是decrypt_file()我的功能.我仍然可以从文件中复制加密文本并将其放入我的decrypt()函数中并使其工作,但是当我尝试使用我应该使用的方便decrypt_file()函数时,它会抛出错误.现在我知道99.999%确定我encrypt()和decrypt()函数都没问题,但是当我读取并编码抛出错误的文本文件时,会有字节和字符串转换的内容; 我只是找不到挂断.请帮忙!
我的计划:
from Crypto import Random
from Crypto.Cipher import AES
def encrypt(message, key=None, key_size=256):
def pad(s):
x = AES.block_size - len(s) % AES.block_size
return s + ((bytes([x])) * x)
padded_message = pad(message)
if key is None:
key = Random.new().read(key_size // 8)
iv = Random.new().read(AES.block_size)
cipher = AES.new(key, AES.MODE_CBC, iv)
return iv + cipher.encrypt(padded_message)
def decrypt(ciphertext, key):
unpad = lambda s: s[:-s[-1]]
iv = ciphertext[:AES.block_size]
cipher = AES.new(key, AES.MODE_CBC, iv)
plaintext = unpad(cipher.decrypt(ciphertext))[AES.block_size:]
return plaintext
def encrypt_file(file_name, key):
f = open(file_name, 'r')
plaintext = f.read()
plaintext = plaintext.encode('utf-8')
enc = encrypt(plaintext, key)
f.close()
f = open(file_name, 'w')
f.write(str(enc))
f.close()
def decrypt_file(file_name, key):
def pad(s):
x = AES.block_size - len(s) % AES.block_size
return s + ((str(bytes([x]))) * x)
f = open(file_name, 'r')
plaintext = f.read()
x = AES.block_size - len(plaintext) % AES.block_size
plaintext += ((bytes([x]))) * x
dec = decrypt(plaintext, key)
f.close()
f = open(file_name, 'w')
f.write(str(dec))
f.close()
key = b'\xbf\xc0\x85)\x10nc\x94\x02)j\xdf\xcb\xc4\x94\x9d(\x9e[EX\xc8\xd5\xbfI{\xa2$\x05(\xd5\x18'
encrypt_file('to_enc.txt', key)
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我加密的文本文件:
b';c\xb0\xe6Wv5!\xa3\xdd\xf0\xb1\xfd2\x90B\x10\xdf\x00\x82\x83\x9d\xbc2\x91\xa7i M\x13\xdc\xa7'
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尝试时出错decrypt_file:
Traceback (most recent call last):
File "C:\Python33\testing\test\crypto.py", line 56, in <module>
decrypt_file('to_enc.txt', key)
File "C:\Python33\testing\test\crypto.py", line 45, in decrypt_file
plaintext += ((bytes([x]))) * x
TypeError: Can't convert 'bytes' object to str implicitly
[Finished in 1.5s]
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当我用:替换第45行时plaintext += ((str(bytes([x])))) * x,这是我得到的错误:
Traceback (most recent call last):
File "C:\Python33\testing\test\crypto.py", line 56, in <module>
decrypt_file('to_enc.txt', key)
File "C:\Python33\testing\test\crypto.py", line 46, in decrypt_file
dec = decrypt(plaintext, key)
File "C:\Python33\testing\test\crypto.py", line 23, in decrypt
plaintext = unpad(cipher.decrypt(ciphertext))[AES.block_size:]
File "C:\Python33\lib\site-packages\Crypto\Cipher\blockalgo.py", line 295, in decrypt
return self._cipher.decrypt(ciphertext)
ValueError: Input strings must be a multiple of 16 in length
[Finished in 1.4s with exit code 1]
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Kei*_*ith 29
我仔细看了一下你的代码,发现它有几个问题.第一个是加密函数带有字节而不是文本.因此,最好将数据保存为字节字符串.只需在模式中输入"b"字符即可完成此操作.这样你就可以摆脱你想要做的所有编码和字节转换.
我还使用较新的Python习语重写了整个代码.这里是.
#!/usr/bin/python3
from Crypto import Random
from Crypto.Cipher import AES
def pad(s):
return s + b"\0" * (AES.block_size - len(s) % AES.block_size)
def encrypt(message, key, key_size=256):
message = pad(message)
iv = Random.new().read(AES.block_size)
cipher = AES.new(key, AES.MODE_CBC, iv)
return iv + cipher.encrypt(message)
def decrypt(ciphertext, key):
iv = ciphertext[:AES.block_size]
cipher = AES.new(key, AES.MODE_CBC, iv)
plaintext = cipher.decrypt(ciphertext[AES.block_size:])
return plaintext.rstrip(b"\0")
def encrypt_file(file_name, key):
with open(file_name, 'rb') as fo:
plaintext = fo.read()
enc = encrypt(plaintext, key)
with open(file_name + ".enc", 'wb') as fo:
fo.write(enc)
def decrypt_file(file_name, key):
with open(file_name, 'rb') as fo:
ciphertext = fo.read()
dec = decrypt(ciphertext, key)
with open(file_name[:-4], 'wb') as fo:
fo.write(dec)
key = b'\xbf\xc0\x85)\x10nc\x94\x02)j\xdf\xcb\xc4\x94\x9d(\x9e[EX\xc8\xd5\xbfI{\xa2$\x05(\xd5\x18'
encrypt_file('to_enc.txt', key)
#decrypt_file('to_enc.txt.enc', key)
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