我试图统一一个ARM项目(特别是运行Linux 2.6.33.3的i.MX27 CPU,用GCC 4.3.2编译)的SQLite交互方法.作为其中的一部分,我创建了一个带有union的结构,该结构用于保存绑定到预准备语句的值.
#define SQLITE_DATA_CHARACTER_STRING_MAX 1024
typedef struct
{
int data_type;
union
{
int integer;
double floating_point;
unsigned char character_string[SQLITE_DATA_CHARACTER_STRING_MAX];
};
}sqlite_data;
Run Code Online (Sandbox Code Playgroud)
原来,这是int,float,char.我想用long long,double和char.但是,这似乎导致了一个问题.如上所述,以下代码生成可预测的输出:
int data_fields = 15;
int data_fields_index = 0;
sqlite_data data[data_fields];
LogMsg(LOG_INFO, "%s: Assigning", __FUNCTION__);
for(data_fields_index = 0; data_fields_index < data_fields; data_fields_index++)
{
data[data_fields_index].data_type = (100 + data_fields_index);
data[data_fields_index].integer = (1000 + data_fields_index);
LogMsg(LOG_INFO, "%s: data[%d] - %d; type - %d", __FUNCTION__, data_fields_index, data[data_fields_index].integer, data[data_fields_index].data_type);
}
Run Code Online (Sandbox Code Playgroud)
其输出是这样的:
Assigning
data[0] - 1000; type - 100
data[1] - 1001; type - 101
data[2] - 1002; type - 102
data[3] - 1003; type - 103
data[4] - 1004; type - 104
data[5] - 1005; type - 105
data[6] - 1006; type - 106
data[7] - 1007; type - 107
data[8] - 1008; type - 108
data[9] - 1009; type - 109
data[10] - 1010; type - 110
data[11] - 1011; type - 111
data[12] - 1012; type - 112
data[13] - 1013; type - 113
data[14] - 1014; type - 114
Run Code Online (Sandbox Code Playgroud)
但是,如果我只进行一次更改(给出integer类型long long),它就会崩溃.那么,以下变化:
typedef struct
{
int data_type;
union
{
long long integer;
double floating_point;
unsigned char character_string[SQLITE_DATA_CHARACTER_STRING_MAX];
};
}sqlite_data;
Run Code Online (Sandbox Code Playgroud)
生成此输出:
Assigning
data[0] - 1000; type - 0
data[1] - 1001; type - 0
data[2] - 1002; type - 0
data[3] - 1003; type - 0
data[4] - 1004; type - 0
data[5] - 1005; type - 0
data[6] - 1006; type - 0
data[7] - 1007; type - 0
data[8] - 1008; type - 0
data[9] - 1009; type - 0
data[10] - 1010; type - 0
data[11] - 1011; type - 0
data[12] - 1012; type - 0
data[13] - 1013; type - 0
data[14] - 1014; type - 0
Run Code Online (Sandbox Code Playgroud)
我已经尝试将它们去实现它们,使用#pragma pack(6)并将该数组放在堆上,所有这些都具有相同的结果:int工作,long long但不是.
这里发生了什么?
你没有告诉printf()期待long long.使用%lld您的格式字符串代替%d.