Android上的图标弹出菜单

Question

我的菜单xml代码menu.xml:

<?xml version="1.0" encoding="utf-8"?><menu xmlns:android="http://schemas.android.com/apk/res/android">
<!-- Single menu item 
     Set id, icon and Title for each menu item
-->

 <item android:id="@+id/back"
      android:icon="@drawable/back1"
        android:showAsAction="never"
      android:title="Back" />

<item android:id="@+id/My_Profile"
      android:icon="@drawable/myprofile"
       android:showAsAction="never"
      android:title="My Profile" />

<item android:id="@+id/Job_Alert"
      android:icon="@drawable/jobalert4"
       android:showAsAction="never"
      android:title="Job Alert !" />

<item android:id="@+id/saved_job"
      android:icon="@drawable/jobapplied"
      android:title="Saved Jobs"
       />


<item android:id="@+id/Logout"
      android:icon="@drawable/logout"
      android:title="Logout" /> 
</menu>

我正在调用这样的菜单xml

     PopupMenu popup = new PopupMenu(getBaseContext(), v);
 popup.getMenuInflater().inflate(R.menu.menu,  popup.getMenu());
     popup.show();

但它没有显示图标.

如何在弹出菜单上设置图标？

Answer 1

您可以使用MenuBuilder和创建带有图标的弹出菜单MenuPopupHelper.

MenuBuilder menuBuilder =new MenuBuilder(this);
MenuInflater inflater = new MenuInflater(this);
inflater.inflate(R.menu.menu, menuBuilder);
MenuPopupHelper optionsMenu = new MenuPopupHelper(this, menuBuilder, view);
optionsMenu.setForceShowIcon(true);

// Set Item Click Listener
menuBuilder.setCallback(new MenuBuilder.Callback() {
    @Override
    public boolean onMenuItemSelected(MenuBuilder menu, MenuItem item) {
        switch (item.getItemId()) {
            case R.id.opt1: // Handle option1 Click
                return true;
            case R.id.opt2: // Handle option2 Click
                return true;
            default:
                return false;
        }
    }

    @Override
    public void onMenuModeChange(MenuBuilder menu) {}
});

optionsMenu.show();

menu.xml文件

<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:android="http://schemas.android.com/apk/res/android">
    <item
        android:id="@+id/opt1"
        android:icon="@mipmap/ic_launcher"
        android:title="option 1" />
    <item
        android:id="@+id/opt2"
        android:icon="@mipmap/ic_launcher"
        android:title="option 2" />
</menu>

Answer 2

您可以通过使用 Java 反射调用隐藏方法来启用弹出菜单的图标，如下所示：

public static void setForceShowIcon(PopupMenu popupMenu) {
    try {
        Field[] fields = popupMenu.getClass().getDeclaredFields();
        for (Field field : fields) {
            if ("mPopup".equals(field.getName())) {
                field.setAccessible(true);
                Object menuPopupHelper = field.get(popupMenu);
                Class<?> classPopupHelper = Class.forName(menuPopupHelper
                        .getClass().getName());
                Method setForceIcons = classPopupHelper.getMethod(
                        "setForceShowIcon", boolean.class);
                setForceIcons.invoke(menuPopupHelper, true);
                break;
            }
        }
    } catch (Throwable e) {
        e.printStackTrace();
    }
}

Answer 3

这是因为当您使用该showAsAction="never"属性时，默认溢出不会返回您的图标。您可以像这样创建自己的溢出：

<item android:title=""
        android:id="@+id/overflow"
        android:showAsAction="always"
        android:icon="@drawable/overflow_icon">
  <menu >    
    <item android:id="@+id/back"
          android:icon="@drawable/back1"
          android:title="Back" />

    <item android:id="@+id/My_Profile"
          android:icon="@drawable/myprofile"
          android:title="My Profile" />

    <item android:id="@+id/Job_Alert"
          android:icon="@drawable/jobalert4"
          android:title="Job Alert !" />

    <item android:id="@+id/saved_job"
          android:icon="@drawable/jobapplied"
          android:title="Saved Job"/>
    <item android:id="@+id/Logout"
          android:icon="@drawable/logout"
          android:title="Logout" /> 
  </menu>
</item>