Mar*_*rkL 1 php mysql laravel-4
回覆,
我有一个典型的多对多关系设置如下:
class Feature extends Eloquent {
public function cars()
{
return $this->belongsToMany('Car', 'car_feature', 'feature_id', 'car_id');
}
}
class Car extends Eloquent {
public function features()
{
return $this->belongsToMany('Feature', 'car_feature', 'car_id', 'feature_id');
}
}
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我试图找到所有具有功能(有些没有)并急切加载模型的汽车:
$cars = Car::with(array('features' => function($query)
{
$query->where("title", "leather");
}))->get();
foreach ($cars as $car) {
return $car;
}
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它执行2个查询:
SELECT * from `cars`;
SELECT `features`.*, `car_feature`.`car_id` as `pivot_car_id`, `car_feature`.`feature_id` as `pivot_feature_id`
FROM `features`
INNER JOIN `car_feature` on `features`.`id` = `car_feature`.`feature_id`
WHERE `car_feature`.`car_id` in (1, 2, ..., 9000) and `title` = 'leather';
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查询没问题,如果我在SQL中运行第二个查询,它会产生我想要的结果.然而,通过退回的物品,它输出所有汽车而不是具有"皮革"作为特征的汽车.是什么赋予了?
谢谢.
谢谢!
如果您使用的是Laravel 4.1,则可以使用以下whereHas方法(未经测试):
$cars = Car::whereHas('features', function($query)
{
$query->where("title", "leather");
})->get();
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