将字符串拆分为向量c ++

Question

我写了一个简单的代码来分割每个'/'的字符串并存储到vector中.我的字符串可以以/或不开头,并且definetelly将以/结尾.例如,如果我的字符串是:

string="/home/desktop/test/" 
I want to <"/","home","desktop","test"> and another example

string="../folder1/folder2/../pic.pdf/" 
I want to store <"..","folder1","folder2","..","pic.pdf"

但是,我的代码给了我 <" ","home","desktop","test"," ">第一个例子和 <"..","folder1","folder2","..","pic.pdf"," ">第二个例子

有人帮我吗？这是我的代码:

#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main()
{
    string strLine("/cd/desktop/../test/");
    string strTempString;
    vector<int> splitIndices;
    vector<string> splitLine;
    int nCharIndex = 0;
    int nLineSize = strLine.size();

    // find indices
    for(int i = 0; i < nLineSize; i++)
    {
        if(strLine[i] == '/')
            splitIndices.push_back(i);
    }
    splitIndices.push_back(nLineSize); // end index

    // fill split lines
    for(int i = 0; i < (int)splitIndices.size(); i++)
    {
        strTempString = strLine.substr(nCharIndex, (splitIndices[i] - nCharIndex));
        splitLine.push_back(strTempString);
        cout << strTempString << endl;
        nCharIndex = splitIndices[i] + 1;
    }


}

Answer 1

C++字符串工具包库(Strtk)具有以下解决方案:

http://www.codeproject.com/Articles/23198/C-String-Toolkit-StrTk-Tokenizer

Answer 2

代码中需要做一些事情来解决这个问题，可能有更好、更优雅的解决方案。

#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main()
{
    string strLine("/cd/desktop/../test/");
    string strTempString;
    vector<int> splitIndices;
    vector<string> splitLine;
    int nCharIndex = 0;
    int nLineSize = strLine.size();

    // find indices
    if(nLineSize!=0 && strLine[0]=='/')
    {
         splitLine.push_back(strLine.substr(0,1));
         nCharIndex++;
    }

    for(int i = 1; i < nLineSize; i++)
    {
        if(strLine[i] == '/')
            splitIndices.push_back(i);
    }

    // fill split lines
    for(int i = 0; i <int(splitIndices.size()); i++)
    {
        strTempString = strLine.substr(nCharIndex, (splitIndices[i] - nCharIndex));
        splitLine.push_back(strTempString);
        nCharIndex = splitIndices[i] + 1;
    }        
}

编辑：稍微清理一下代码，您现在可以删除添加最后一个索引部分。

编辑2：

一个可能更优雅的解决方案可能是删除 ncharcounter 并使用分割索引。如果第一个字符不是（“/”），则可以将第一个值存储为“-1”；如果是，则可以将第一个值存储为（“0”）。

    string strLine("/cd/desktop/../test/");
    string strTempString;
    vector<int> splitIndices;
    vector<string> splitLine;
    int nLineSize = strLine.size();

    // find indices
    splitIndices.push_back(-1);
    if(nLineSize!=0 && strLine[0]=='/')
    {
         splitLine.push_back(strLine.substr(0,1));
         splitIndices[0]=0;
    }             
    for(int i = 1; i < nLineSize; i++)
    {
        if(strLine[i] == '/')
            splitIndices.push_back(i);
    }

    // fill split lines
    for(int i = 1; i <int(splitIndices.size()); i++)
    {
        strTempString = strLine.substr(splitIndices[i-1]+1, (splitIndices[i] - (splitIndices[i-1]+1) ));
        splitLine.push_back(strTempString);
    }