h q*_*h q 8 arrays perl hash ref perl-data-structures
我有一个$subscribers
可能是undef 的标量,引用HASH或引用ARRAY.我已经分配了样本值$VAR1
,$VAR2
并$VAR3
进行了测试.
我只$subscribers
对它是ARRAY的引用感兴趣,其中它包含多个值.在其他情况下,我对打印任何东西都不感兴趣(例如$subscribers=$VAR2;
在Perl v5.16.2下,代码似乎运行良好; 但是,当我将它移动到运行Perl v5.8.8的目标机器时,我收到编译错误:
% ./test.pl
Type of arg 1 to keys must be hash (not private variable) at ./test.pl line 23, near "$subscribers) "
Execution of ./test.pl aborted due to compilation errors.
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代码如下:
#!/usr/bin/perl -w
use strict;
use warnings;
use Data::Dumper;
my $VAR1 = undef;
my $VAR2 = {'msisdn' => '1234'};
my $VAR3 = [
{'msisdn' => '1111'},
{'msisdn' => '2222'},
{'msisdn' => '3333'},
{'msisdn' => '4444'},
{'msisdn' => '5555'}
];
my @childMsisdn = ();
my $subscribers = $VAR3;
if (ref $subscribers eq ref []) { # Exclude $VAR1 && $VAR2 scenarios
foreach my $s (keys $subscribers) {
my $msisdn = $subscribers->[$s]->{"msisdn"};
push (@childMsisdn, $msisdn);
}
}
print "childMsisdn = ". join(",", @childMsisdn) ."\n";
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Сух*_*й27 16
更换
foreach my $s (keys $subscribers) {
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同
foreach my $s (keys %$subscribers) { # $subscribers is hash ref
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要么
foreach my $s (0 .. $#$subscribers) { # $subscribers is array ref
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来自perldoc
从Perl 5.14开始,密钥可以采用标量EXPR,它必须包含对未经处理的散列或数组的引用.该参数将自动解除引用.钥匙的这个方面被认为是高度实验性的.在未来的Perl版本中,确切的行为可能会发生变化.