Sha*_*ari 6 html javascript jquery
我想用Java脚本,HTML和jQuery其显示创建动态矩阵类型的数据显示在这里.
var reservations = [
{"date":"22-12-2013","MCHC":"22","Pulse rate":"75","weight":"50" },
{"date":"11-12-2013","CBC":"5"},
{"date":"11-12-2013","weight":"55"}
];
var tbody = $('#reservations tbody'),
props = ["date", "MCHC", "CBC", "Pulse rate", "weight"];
$.each(reservations, function(i, reservation) {
var tr = $('<tr>');
$.each(props, function(i, prop) {
$('<td>').html(reservation[prop]).appendTo(tr);
});
tbody.append(tr);
});
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问题是代码工作正常但它不显示基于日期的唯一数据.例如,如上所示链接"日期:11-12-2013"重复两次,我不想要.我想显示独特的数据.
我想要的输出是:

试试这个
var reservations = [
{"date":"22-12-2013","MCHC":"22","Pulse rate":"75","weight":"50" },
{"date":"11-12-2013","CBC":"5"},
{"date":"11-12-2013","weight":"55"}
];
var tbody = $('#reservations tbody'),
props = ["date", "MCHC", "CBC", "Pulse rate", "weight"];
$.each(reservations, function(i, reservation) {
var trid = reservation["date"];
if($("#"+trid).length <= 0) {
var tr = $('<tr>').attr("id",trid);
$.each(props, function(i, prop) {
var tdid = prop.replace(/\s/g, '');
$('<td>').html(reservation[prop]).attr("id",tdid).appendTo(tr);
});
tbody.append(tr);
}
else {
$.each(props, function(i, prop) {
var tdid = prop.replace(/\s/g, '');
$("#"+trid).find("td#"+tdid).html(reservation[prop])
});
}
});
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