Gil*_*ald 0 python random dictionary shuffle
从列表中创建字典时,我使用
for i in range(10):
random.shuffle(list)
print "".join(list)
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这样我就得到了10个不同的列表随机组合,但是如果列表有10个字符串,那么每个随机我会得到10个字符串,如下所示:
>>> list
['1', 'n', 'f', 'g', 'z', 'j', '5', 's', '2', '3']
>>> for i in range(5):
... random.shuffle(list)
... print "".join(list)
...
13jgzs25nf
15zngs2jf3
jgfsn3z251
g3sf512zjn
5nsj3fg21z
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但是,我只想要从列表中的10个字符串中只编写5个随机组合,我该怎么做呢?
TY!
==========================
@volatility
in an attempt to use what you showed me but try to get a full list like i did in my question i did this:
>>> lst=["1","2","3","f","s","g","5","n","z","j"]
>>> for i in range(10):
... random.sample(list, 3)
... print "".join(list)
...
['5', '2', 'n']
gj5nfs231z
['n', '5', '1']
gj5nfs231z
['z', '3', 'j']
gj5nfs231z
['5', 'g', 'n']
gj5nfs231z
['g', 'z', '2']
gj5nfs231z
['2', '3', 'f']
gj5nfs231z
['g', '2', '5']
gj5nfs231z
['3', 'n', '2']
gj5nfs231z
['g', 'z', '2']
gj5nfs231z
['n', 's', 'g']
gj5nfs231z
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这是进步,我猜?我最终想得到的是一个看起来像这样的输入(如果我使用上面的列表)
52n
z3j
5gn
23f
g25
3n2
gz2
nsg
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那是可行的吗?
你可以用random.sample它:
>>> lst = ['1', 'n', 'f', 'g', 'z', 'j', '5', 's', '2', '3']
>>> import random
>>> random.sample(lst, 5)
['f', 's', '3', 'z', 'n']
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要获得所需的输出,您可以简单地将其放入for循环中:
>>> for i in range(10):
... print ''.join(random.sample(lst, 5))
...
jn513
13g2f
nfsj5
nj3s1
3zn51
sgj2f
5ns3g
sg51z
23j1z
n2g53
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附注:不要list用作变量名 - 它会影响内置list类型.
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