如何使用带有presentViewController的后退按钮？

Question

这是我的代码,用于调用包含在UINavigationController中的新视图控制器.我想在restaurantResults控制器上有一个简单的后退按钮.我的选择器似乎不起作用.我尝试过使用pop命令.这些工作是否可以使用presentViewController,而不是任何类型的推送？

很确定我的选择器现在是错的,因为它说的是self.navigationController,它可能不对.

这是我调用新视图控制器并设置后退按钮的位置:

 - (void)searchBarSearchButtonClicked:(UISearchBar *)foodNearSearchBar
{

 restaurantsViewController *restaurantResults = [[restaurantsViewController alloc] init];
    UINavigationController *navController = [[UINavigationController alloc] initWithRootViewController:restaurantResults];


    UIBarButtonItem *backButton = [[UIBarButtonItem alloc] initWithTitle:@"Back"
                                                                   style:UIBarButtonItemStyleBordered
                                                                  target:nil
                                                                  action:@selector(backPressed:)];

    restaurantResults.navigationItem.leftBarButtonItem = backButton;


    [self presentViewController:navController animated:YES completion:Nil];

}

这是我的选择器:

   -(void)backPressed: (id)sender
{
    [self.navigationController popViewControllerAnimated: YES]; // or popToRoot... if required.
}

我也尝试过:

 - (void)backPressed:(id)sender
    {
        [self dismissViewControllerAnimated:YES completion:nil];
    };

Answer 1

UIBarButtonItem *backButton = [[UIBarButtonItem alloc] initWithTitle:@"Back"
                                                        style:UIBarButtonItemStyleBordered
                                                       target:nil
                                                        ction:@selector(backPressed:)];

restaurantResults.navigationItem.leftBarButtonItem = backButton;

这些代码应该用在restaurantViewController上；目标是自我。