将Java移植到Python的更好方法？

Question

将Java移植到Python的更好方法？

Noc*_*wer 1 python java porting servlets

经过几个小时的工作来移植这个程序后,它似乎终于处于工作状态.但是,我想知道是否有人知道更好的方法或更完整的方式将Java servlet移植到Python中.Python脚本的开头包含许多支持代码,以便更容易将程序逐行移植到Python中.有谁知道更好的方法来解决这个问题？

Java的

// --------------------------------------------------------
// File: Hello.java
// Description: A simple "Hello World" servlet
// --------------------------------------------------------

import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;
import sun.servlet.http.HttpServer;

public class Hello extends HttpServlet {

  int count;

  public void service(HttpServletRequest request, 
         HttpServletResponse response) throws ServletException, IOException {

    // setup response

    response.setContentType("text/html");
    PrintWriter out = response.getWriter();

    // send response

    out.println("<html><body>");
    out.println("<h5>Stephen Paul Chappell (SPC)</h5>");
    out.println("<h5>:) (ZTD) Zero The Dragon :(</h5>");
    String name = request.getParameter("NAME");
    if (name != null && !name.equals("")) {
      out.println("<h2>Hello, " + name + "</h2>");
    } else {
      out.println();
      if (name != null && name.equals("")) {
        out.println("  <h2>You didn't enter your name. Please enter your name. </h2>");
      } else {
        out.println("  <h2>What's your name? </h2>");
      }
      out.println("  <hr>");
      out.println("  <form action=\"http://127.0.0.1:8080/servlet/Hello\">");
      out.println();
      out.println("    Enter your name: <input type=\"text\" name=\"NAME\" value=\"Fred\"><br>");
      out.println("    <input type=\"submit\" value=\"Click for greeting\">");
      out.println();
      out.println("  </form>");
    }
    String color = request.getParameter("FAVCOLOR");
    if (color != null) {
      out.println("<h2>Why, " + color + " is my favorite color too!</h2>");
    }

    count++;
    out.println("This page has been hit " + count + " time(s).");

    out.print("</body></html>");
  }

  // start web server
  public static void main(String[] args) throws Exception {
    HttpServer.main(args);
  }
}

Run Code Online (Sandbox Code Playgroud)

蟒蛇

import urllib.parse
import http.server
import cgitb
import sys
import io

################################################################################

class HttpServlet(http.server.BaseHTTPRequestHandler):

    __debug = False

    @staticmethod
    def debug(value):
        HttpServlet.__debug = value

    def do_GET(self):
        if self.path == '/favicon.ico':
            self.send_error(404)
            return
        request = HttpServletRequest(self.path)
        response = HttpServletResponse()
        try:
            self.service(request, response)
        except Exception:
            if HttpServlet.__debug:
                self.send_response(500)
                self.send_header('Content-type', 'text/html')
                self.end_headers()
                klass, value, trace = sys.exc_info()
                html = cgitb.html((klass, value, trace.tb_next))
                self.wfile.write(html.encode())
            else:
                self.send_error(500)
        else:
            self.send_response(200)
            self.send_header('Content-type', response._type)
            self.end_headers()
            self.wfile.write(response._value)

    def service(self, request, response):
        raise NotImplementedError()

################################################################################

class HttpServletRequest:

    def __init__(self, path):
        query = urllib.parse.urlparse(path).query
        self.__dict = urllib.parse.parse_qs(query, True)

    def getParameter(self, name):
        return self.__dict.get(name, [None])[0]

################################################################################

class HttpServletResponse:

    def __init__(self):
        self.__content_type = 'text/plain'
        self.__print_writer = PrintWriter()

    def setContentType(self, content_type):
        self.__content_type = content_type

    def getWriter(self):
        return self.__print_writer

    @property
    def _type(self):
        return self.__content_type

    @property
    def _value(self):
        return self.__print_writer.getvalue().encode()

################################################################################

class PrintWriter(io.StringIO):

    print = io.StringIO.write

    def println(self, string):
        self.write(string + '\r\n')

################################################################################

class HttpServer(http.server.HTTPServer):

    @staticmethod
    def main(RequestHandlerClass, port=80):
        server = HttpServer(('', port), RequestHandlerClass)
        socket = server.socket.getsockname()
        print('Serving HTTP on', socket[0], 'port', socket[1], '...')
        try:
            server.serve_forever()
        except KeyboardInterrupt:
            print('Keyboard interrupt received: EXITING')
            server.server_close()

################################################################################
################################################################################

## ---------------------------------------------------------
## File: Hello.py
## Description: A simple "Hello World" servlet
## ---------------------------------------------------------

class Hello(HttpServlet):

    count = 0

    def service(self, request, response):

        # Setup for a response.
        response.setContentType('text/html')
        out = response.getWriter()

        # Send an appropriate response.
        out.println('''\
<html>
    <head>
        <title>Java to Python servlet</title>
    </head>
    <body>
        <h5>Stephen Paul Chappell (SPC)</h5>
        <h5>:) (ZTD) Zero The Dragon :(</h5>''')
        name = request.getParameter('NAME')
        if name:
            out.println('''\
        <h2>Hello, {}!</h2>'''.format(name))
        else:
            if name == '':
                out.println('''\
        <h2>You did not enter your name.</h2>
        <h3>Please enter your name.</h3>''')
            else:
                out.println('''\
        <h2>What is your name?</h2>''')
            out.println('''\
        <form>
            <fieldset>
                <legend>About Yourself</legend>
                <label for='NAME'>Enter your name:</label>
                <input id='NAME' name='NAME' type='text' value='John Doe' />
                <br />
                <input type='submit' value='Click me!' />
            </fieldset>
        </form>''')
        color = request.getParameter('FAVCOLOR')
        if color:
            out.println('''\
        <h2>Why, {} is my favorite color too!</h2>'''.format(color))

        Hello.count += 1
        out.println('''\
        This page has been hit {} times.'''.format(Hello.count))

        out.print('''\
    </body>
</html>''')

# Start the web server.
def main():
    HttpServlet.debug(True)
    HttpServer.main(Hello)

################################################################################

if __name__ == '__main__':
    main()

Run Code Online (Sandbox Code Playgroud)

如果有人想知道这个项目的目的是什么,最初的Java程序是作为新生级计算机科学课程的入门练习.从那时起,我已经用了大约六年的时间与Java合作并且正在完成旧程序,将它们移植到Python以获得挑战和学习经验.移植servlet会带来额外的困难.

Answer 1

Tra*_*haw 5

我最好的建议是不要逐行写入.如果您只是在Python语言中编写Java样式代码,那么Python就不是Java而且您自己也在喋喋不休.

以下是识别一些常见差异/错误的起点:http://dirtsimple.org/2004/12/python-is-not-java.html

如果你很幸运能够使用包含单元测试的代码库,那么解决这个问题的一个好方法是将单元测试从Java移植到Python,然后编写新的python以匹配单元测试.如果这是不是你有什么事情的话,就能够识别软件什么是更重要的做在Java中,然后编写Python代码,做同样的事情.它几乎肯定不会以同样的方式,至少不是逐行的.

归档时间：	15 年，10 月前
查看次数：	4017 次
最近记录：	8 年，5 月前