这个语法是什么,初始化一个接口,因为它是一个类数组？(新的IItemTransform [0])

Question

在System.Web.Optimization.Bundle中找到新的IItemTransform [0].我试图谷歌搜索有关此语法的任何内容,但由于过于通用的单词的搜索查询而没有成功.

public virtual Bundle IncludeDirectory(string directoryVirtualPath, string searchPattern, bool searchSubdirectories)
    {
      if (ExceptionUtil.IsPureWildcardSearchPattern(searchPattern))
        throw new ArgumentException(OptimizationResources.InvalidWildcardSearchPattern, "searchPattern");
      PatternType patternType = PatternHelper.GetPatternType(searchPattern);
      Exception exception1 = PatternHelper.ValidatePattern(patternType, searchPattern, "virtualPaths");
      if (exception1 != null)
        throw exception1;
      Exception exception2 = this.Items.IncludeDirectory(directoryVirtualPath, searchPattern, patternType, searchSubdirectories, new IItemTransform[0]);
      if (exception2 != null)
        throw exception2;
      else
        return this;
    }

IItemTransform:

namespace System.Web.Optimization
{
  public interface IItemTransform
  {
    string Process(string includedVirtualPath, string input);
  }
}

这种感觉真的不直观,有没有人认识到语法？

Answer 1

new IItemTransform[0]只是创建一个类型的引用数组(大小为零)IItemTransform.它不会创建任何实现的对象IItemTransform.

它在语法上与创建一个空字符串数组相同:

string[] foo;
foo = new string[0];

它只是一个阵列而IItemTransform不是string.