需要有关python列表操作的帮助

Question

我有两个单独的名单

list1 = ["Infantry","Tanks","Jets"]
list2 = [ 10, 20, 30]

所以实际上,我有10个步兵,20个坦克和30个喷气机

我想创建一个类,以便最后,我可以这样称呼:

for unit in units:
  print unit.amount
  print unit.name

#and it will produce:  
#  10 Infantry  
#  20 Tanks  
#  30 Jets  

所以我们的目标是将list1和list2组合成一个可以轻松调用的类.

在过去3小时内尝试了很多组合,没有什么好结果:(

Answer 1

class Unit(object):
  def __init__(self, amount, name):
    self.amount = amount
    self.name = name

units = [Unit(a, n) for (a, n) in zip(list2, list1)]

Answer 2

from collections import namedtuple

Unit = namedtuple("Unit", "name, amount")
units = [Unit(*v) for v in zip(list1, list2)]

for unit in units:
  print "%4d %s" % (unit.amount, unit.name)

亚历克斯在我可以之前指出了一些细节.

Answer 3

这应该这样做:

class Unit:
  """Very simple class to track a unit name, and an associated count."""
  def __init__(self, name, amount):
   self.name = name
   self.amount = amount

# Pre-existing lists of types and amounts.    
list1 = ["Infantry", "Tanks", "Jets"]
list2 = [ 10, 20, 30]

# Create a list of Unit objects, and initialize using
# pairs from the above lists.    
units = []
for a, b in zip(list1, list2):
  units.append(Unit(a, b))

Answer 4

在Python 2.6中,我建议使用一个名为tuple的代码 - 比编写简单类更少的代码,并且在内存使用方面也非常节俭:

import collections

Unit = collections.namedtuple('Unit', 'amount name')

units = [Unit(a, n) for a, n in zip(list2, list1)]

当一个类有一组固定的字段(不需要它的实例是"可扩展的",每个实例有新的任意字段)而没有特定的"行为"(即,没有必要的特定方法)时,考虑使用一个命名的元组类型相反(唉,在Python 2.5或更早版本中不可用,如果你坚持使用;-).