声明任何标准变量时,SDL崩溃

use*_*885 0 c crash sdl sdl-2

这个SDL程序运行正常(显示一个窗口并在其上绘制一个位图),但是,如果我在程序中声明任何变量(例如int,long等),窗口会冻结并且是白色而不是黑色而且没有任何绘制.有什么可能导致这种情况?

#include <stdio.h>
#include <SDL2/SDL.h>
#include <SDL2/SDL_image.h>

int main(int argc, char* argv[]) {
    // line below will cause SDL crash
    // int blabla = 640; 
    SDL_Window *window;
    SDL_Init(SDL_INIT_VIDEO);
    window = SDL_CreateWindow(
        "A rather exceptional SDL window",
        SDL_WINDOWPOS_UNDEFINED,
        SDL_WINDOWPOS_UNDEFINED,
        640,
        480,
        SDL_WINDOW_OPENGL
    );
    if (window == NULL) {
        printf("Could not create window: %s\n", SDL_GetError());
        return 1;
    }
    SDL_Renderer *renderer;
    SDL_Texture *texture;
    renderer = SDL_CreateRenderer(window, -1, SDL_RENDERER_ACCELERATED);
    SDL_Surface *brush;
    brush = IMG_Load("brush2.png");
    texture = SDL_CreateTextureFromSurface(renderer, brush);
    SDL_RenderClear(renderer);
    SDL_Rect *sRect, *dRect;
    sRect->w = 10;
    sRect->h = 4;
    sRect->x = 0;
    sRect->y = 0;
    dRect->w = 10;
    dRect->h = 4;
    dRect->x = 10;
    dRect->y = 10;
    SDL_RenderCopy(renderer, texture, sRect, dRect);
    SDL_RenderPresent(renderer);
    SDL_Delay(1000);
    SDL_DestroyWindow(window);
    SDL_Quit();
    return 0;
}
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use*_*733 6

您正在编写未分配的内存.

SDL_Rect *sRect, *dRect;
sRect->w = 10; /* w doesn't exist. Writing is undefined behaviour. */
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sRect并且dRect只是指针.在访问struct成员之前,他们需要指向有效的内存.

您可以在堆栈中声明它们:

SDL_Rect sRect, dRect;
sRect.w = 10;
sRect.h = 4;
...
SDL_RenderCopy(renderer, texture, &sRect, &dRect);
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您还应该检查SDL_-functions的返回值.如果这些失败,并且您继续执行,则可能会遇到奇怪的行为或崩溃.

  • `sRect-> w = 10;`写入未分配的区域.这将导致未定义的行为.这意味着**任何**都可能发生.它可能有用,它可能无法工作,它可能会因完全不相关的原因而崩溃.声明变量`blabla`最有可能改变`sRect`在堆栈上的位置,这意味着指针的初始(垃圾)值是不同的.它起初工作是纯粹的运气. (2认同)