转换内容在CDATA内的xml元素

jje*_*fer 8 xml xslt cdata

我有一个像下面的xml片段

<Detail uid="6">
    <![CDATA[
    <div class="heading">welcome to my page</div>
    <div class="paragraph">this is paraph</div>
    ]]>
</Detail>
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我希望能够改变

<div class="heading">...</div> to <h1>Welcome to my page</h1>
<div class="paragraph">...</div> to <p>this is paragraph</p>
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你知道我怎么能在xslt 1.0中做到这一点

Mad*_*sen 9

怎么样运行两个转换.

通过1.)

<?xml version="1.0" encoding="UTF-8"?>
  <xsl:stylesheet
   version="1.0"
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="yes" encoding="UTF-8"/>

  <xsl:template match="/">
    <xsl:apply-templates />
  </xsl:template>

    <xsl:template match="Detail">
        <Detail>
            <xsl:copy-of select="@*"/>
        <xsl:value-of select="." disable-output-escaping="yes" />
        </Detail>
    </xsl:template>

</xsl:stylesheet>
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会产生:

<?xml version="1.0" encoding="UTF-8"?>
<Detail uid="6"> 
    <div class="heading">welcome to my page</div>
    <div class="paragraph">this is paraph</div>
</Detail>
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通过2.)

<?xml version="1.0" encoding="UTF-8"?>
  <xsl:stylesheet
   version="1.0"
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="yes" encoding="UTF-8"/>

  <xsl:template match="/">
    <xsl:apply-templates />
  </xsl:template>

    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*| node()" />
        </xsl:copy>
    </xsl:template>

    <xsl:template match="div[@class='heading']">
        <h1><xsl:value-of select="."/></h1>
    </xsl:template>

    <xsl:template match="div[@class='paragraph']">
        <p><xsl:value-of select="."/></p>
    </xsl:template>

</xsl:stylesheet>
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生产:

<?xml version="1.0" encoding="UTF-8"?>
<Detail uid="6">
<h1>welcome to my page</h1>
<p>this is paraph</p>
</Detail>
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