Python PySide和进度条线程

Question

我有这个代码:

from PySide import QtCore, QtGui
import time

class Ui_Dialog(object):
    def setupUi(self, Dialog):
        Dialog.setObjectName("Dialog")
        Dialog.resize(400, 133)
        self.progressBar = QtGui.QProgressBar(Dialog)
        self.progressBar.setGeometry(QtCore.QRect(20, 10, 361, 23))
        self.progressBar.setProperty("value", 24)
        self.progressBar.setObjectName("progressBar")
        self.pushButton = QtGui.QPushButton(Dialog)
        self.pushButton.setGeometry(QtCore.QRect(20, 40, 361, 61))
        self.pushButton.setObjectName("pushButton")

        self.retranslateUi(Dialog)
        QtCore.QMetaObject.connectSlotsByName(Dialog)

    def retranslateUi(self, Dialog):
        Dialog.setWindowTitle(QtGui.QApplication.translate("Dialog", "Dialog", None, QtGui.QApplication.UnicodeUTF8))
        self.pushButton.setText(QtGui.QApplication.translate("Dialog", "PushButton", None, QtGui.QApplication.UnicodeUTF8))
        self.progressBar.setValue(0)
        self.pushButton.clicked.connect(self.progress)

    def progress(self):
        self.progressBar.minimum = 1
        self.progressBar.maximum = 100
        for i in range(1, 101):
            self.progressBar.setValue(i)
            time.sleep(0.1)

if __name__ == "__main__":
    import sys
    app = QtGui.QApplication(sys.argv)
    Dialog = QtGui.QDialog()
    ui = Ui_Dialog()
    ui.setupUi(Dialog)
    Dialog.show()
    sys.exit(app.exec_())

我希望在一个单独的线程中有进度条,所以它不会冻结应用程序,但我似乎无法找到如何这样做.

有人可以帮忙吗？

Answer 1

我想你可能弄错了.您希望在单独的线程中执行的工作因此不会冻结应用程序.但您也希望能够更新进度条.您可以通过使用a创建工作类来实现此目的QThread.QThreads能够发出信号,您的UI可以监听并采取适当的行动.

首先,让我们创建你的工人类.

#Inherit from QThread
class Worker(QtCore.QThread):

    #This is the signal that will be emitted during the processing.
    #By including int as an argument, it lets the signal know to expect
    #an integer argument when emitting.
    updateProgress = QtCore.Signal(int)

    #You can do any extra things in this init you need, but for this example
    #nothing else needs to be done expect call the super's init
    def __init__(self):
        QtCore.QThread.__init__(self)

    #A QThread is run by calling it's start() function, which calls this run()
    #function in it's own "thread". 
    def run(self):
        #Notice this is the same thing you were doing in your progress() function
        for i in range(1, 101):
            #Emit the signal so it can be received on the UI side.
            self.updateProgress.emit(i)
            time.sleep(0.1)

所以现在你有了一个工人阶级,是时候利用它了.您需要在Ui_Dialog类中创建一个新函数来处理发出的信号.

def setProgress(self, progress):
    self.progressBar.setValue(progress)

当你在那里时,你可以删除你的progress()功能.

在retranslateUi()你想要更新按钮事件处理程序

self.pushButton.clicked.connect(self.progress)

至

self.pushButton.clicked.connect(self.worker.start)

最后,在您的setupUI()函数中,您需要创建worker类的实例并将其信号连接到您的setProgress()函数.

在这之前:

self.retranslateUi(Dialog)

添加这个:

self.worker = Worker()
self.worker.updateProgress.connect(self.setProgress)

这是最终的代码:

from PySide import QtCore, QtGui
import time


class Ui_Dialog(object):
    def setupUi(self, Dialog):
        Dialog.setObjectName("Dialog")
        Dialog.resize(400, 133)
        self.progressBar = QtGui.QProgressBar(Dialog)
        self.progressBar.setGeometry(QtCore.QRect(20, 10, 361, 23))
        self.progressBar.setProperty("value", 24)
        self.progressBar.setObjectName("progressBar")
        self.pushButton = QtGui.QPushButton(Dialog)
        self.pushButton.setGeometry(QtCore.QRect(20, 40, 361, 61))
        self.pushButton.setObjectName("pushButton")

        self.worker = Worker()
        self.worker.updateProgress.connect(self.setProgress)

        self.retranslateUi(Dialog)
        QtCore.QMetaObject.connectSlotsByName(Dialog)

        self.progressBar.minimum = 1
        self.progressBar.maximum = 100

    def retranslateUi(self, Dialog):
        Dialog.setWindowTitle(QtGui.QApplication.translate("Dialog", "Dialog", None, QtGui.QApplication.UnicodeUTF8))
        self.pushButton.setText(QtGui.QApplication.translate("Dialog", "PushButton", None, QtGui.QApplication.UnicodeUTF8))
        self.progressBar.setValue(0)
        self.pushButton.clicked.connect(self.worker.start)

    def setProgress(self, progress):
        self.progressBar.setValue(progress)

#Inherit from QThread
class Worker(QtCore.QThread):

    #This is the signal that will be emitted during the processing.
    #By including int as an argument, it lets the signal know to expect
    #an integer argument when emitting.
    updateProgress = QtCore.Signal(int)

    #You can do any extra things in this init you need, but for this example
    #nothing else needs to be done expect call the super's init
    def __init__(self):
        QtCore.QThread.__init__(self)

    #A QThread is run by calling it's start() function, which calls this run()
    #function in it's own "thread". 
    def run(self):
        #Notice this is the same thing you were doing in your progress() function
        for i in range(1, 101):
            #Emit the signal so it can be received on the UI side.
            self.updateProgress.emit(i)
            time.sleep(0.1)

if __name__ == "__main__":
    import sys
    app = QtGui.QApplication(sys.argv)
    Dialog = QtGui.QDialog()
    ui = Ui_Dialog()
    ui.setupUi(Dialog)
    Dialog.show()
    sys.exit(app.exec_())

QThreads有一些自动发出的内置信号.您可以在文档中看到它们以及有关QThreads的更多信息

Answer 2

认为你总是需要使用多线程来做这样的事情是错误的.

如果您可以将长时间运行的任务分解为一系列小步骤,那么您需要做的就是确保经常处理任何待处理事件,以便GUI保持响应.这可以安全地从完成内主界面线程使用processEvents,就像这样:

    for i in range(1, 101):
        self.progressBar.setValue(i)
        QtGui.qApp.processEvents()
        time.sleep(0.1)

鉴于它的简单性,在选择更多重量级解决方案(如多线程或多处理)之前,至少考虑这种技术总是值得的.