从django admin list_display访问,这是One-To-One表中的值

Bry*_*yce 9 django django-admin django-1.5

给定一对一扩展模型,例如Django User模型:

class UserProfile(models.Model):
     user        = models.OneToOneField(User, related_name='profile', unique=True)
     avatar      = models.ImageField(_('Avatar'))
     foo         = models.CharField(max_length=100, verbose_name="xxx")
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如何在管理员中显示?

class UserAdmin(admin.ModelAdmin):
     list_display = ('email', 'profile__foo' <--NOT WORKING )
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一个近乎匹配的问题是Django Admin:如何用两个处于oneToOne关系的模型显示list_display的字段值?

yuv*_*uvi 16

一般方法是:

class UseAdmin(admin.ModelAdmin):
    list_display = ('email', 'profile_foo')
    def profile_foo(self, x):
        return x.profile.foo
    profile_foo.short_description = 'foo'
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x这是您正在显示的模型的对象