Bry*_*yce 9 django django-admin django-1.5
给定一对一扩展模型,例如Django User模型:
class UserProfile(models.Model):
user = models.OneToOneField(User, related_name='profile', unique=True)
avatar = models.ImageField(_('Avatar'))
foo = models.CharField(max_length=100, verbose_name="xxx")
Run Code Online (Sandbox Code Playgroud)
如何在管理员中显示?
class UserAdmin(admin.ModelAdmin):
list_display = ('email', 'profile__foo' <--NOT WORKING )
Run Code Online (Sandbox Code Playgroud)
一个近乎匹配的问题是Django Admin:如何用两个处于oneToOne关系的模型显示list_display的字段值?
yuv*_*uvi 16
一般方法是:
class UseAdmin(admin.ModelAdmin):
list_display = ('email', 'profile_foo')
def profile_foo(self, x):
return x.profile.foo
profile_foo.short_description = 'foo'
Run Code Online (Sandbox Code Playgroud)
x这是您正在显示的模型的对象