如何将小数部分转换为十六进制分数？

Question

所以我在想,你如何将小数部分转换为十六进制分数？什么是转换的方法,有没有捷径？

Answer 1

您可以使用此算法:

1. 取一个小数部分(即整数部分等于零)
2. 乘以16
3. 将整数部分转换为十六进制并将其放下
4. 转到第1步

例如,让我们找出pi = 3.141592653589793的十六进制表示...

整数部分很明显 - 0x3 ; 至于小数部分(0.141592653589793)我们有

  0.14159265358979 * 16 =  2.26548245743664; int part  2 (0x2); frac 0.26548245743664
  0.26548245743664 * 16 =  4.24771931898624; int part  4 (0x4); frac 0.24771931898624
  0.24771931898624 * 16 =  3.96350910377984; int part  3 (0x3); frac 0.96350910377984
  0.96350910377984 * 16 = 15.41614566047744; int part 15 (0xF); frac 0.41614566047744
  0.41614566047744 * 16 =  6.65833056763904; int part  6 (0x6); frac 0.65833056763904
  0.65833056763904 * 16 = 10.53328908222464; int part 10 (0xA); ...

所以pi(十六进制)= 3.243F6A ......

可能的(C#)实现

public static String ToHex(Double value) {
  StringBuilder Sb = new StringBuilder();

  if (value < 0) {
    Sb.Append('-');

    value = -value;
  }

  // I'm sure you know how to convert decimal integer to its hexadecimal representation
  BigInteger bi = (BigInteger) value;
  Sb.Append(bi.ToString("X"));

  value = value - (Double)bi;

  // We have integer value in fact (e.g. 5.0)
  if (value == 0)
    return Sb.ToString();

  Sb.Append('.');

  // Double is 8 byte and so has at most 16 hexadecimal values
  for (int i = 0; i < 16; ++i) {
    value = value * 16;
    int digit = (int) value;

    Sb.Append(digit.ToString("X"));

    value = value - digit;

    if (value == 0)
      break;
  }

  return Sb.ToString();
}

测试

   Console.Write(ToHex(Math.PI)); // <- returns "3.243F6A8885A3"