Qbi*_*ite 6 flask wtforms twitter-bootstrap-3
我在Twitter Bootstrap 3模式中有一个WTF表单,我需要验证.问题是,即使存在验证错误,用户提交表单时模式也会关闭.如果我再次单击触发模态的按钮,则会显示验证错误.所以我的问题是,当有验证错误时,如何让模态保持打开状态?谢谢!
<button type="button" class="btn btn-default" data-toggle="modal" role="dialog" data-target="#save">
<span class="glyphicon glyphicon-flash"></span>
</button>
<div class="modal fade" id="save" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>
<h3 class="modal-title" id="myModalLabel">Archive List and Start New</h3>
</div>
<form role="form_list" class="form form-medium" action="." method="post">
{{ form_save.csrf_token }}
<div class="modal-body">
<h4>Save list as: </h4>
{{ render_field(form_save.list_name, class="input-large") }}
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
<a href="#">
<button class="btn btn-success">Archive List</button></a>
</div>
</form>
</div><!-- modal content -->
</div><!-- modal-dialog -->
</div><!-- modal -->
<script src="{{ url_for('static', filename='js/jquery.js') }}"></script>
<script src="{{ url_for('static', filename='js/bootstrap.min.js') }}"></script>
Run Code Online (Sandbox Code Playgroud)
b4s*_*ien 11
你应该添加一些javascript,以便在表单中出现错误时自动打开模态.
像(使用jQuery):
var formErrors = {% if form_errors %}true{% else %}false{% endif %};
$(document).ready(function() {
if (formErrors) {
$('.modal').modal('show');
}
});
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
3246 次 |
| 最近记录: |