soa*_*dos 28 c++ libstdc++ clang++ msan memory-sanitizer
我希望使用-fsanitize=memoryclang中的标志来分析如下的程序:
#include <string>
#include <iostream>
#include <fstream>
using namespace std;
void writeToFile(){
ofstream o;
o.open("dum");
o<<"test"<<endl; //The error is here.
//It does not matter if the file is opened this way,
//or with o("dum");
o.close();
}
int main(){
writeToFile();
}
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据我所知,这个程序是正确的,但是当我使用clang++ san.cpp -fsanitize=memory它时失败(在运行时):
UMR in __interceptor_write at offset 0 inside [0x64800000e000, +5)
==9685== WARNING: MemorySanitizer: use-of-uninitialized-value
#0 0x7f48d0899ae5 (/usr/lib/x86_64-linux-gnu/libstdc++.so.6+0x7bae5)
#1 0x7f48d08d1787 (/usr/lib/x86_64-linux-gnu/libstdc++.so.6+0xb3787)
#2 0x7f48d08d21e2 (/usr/lib/x86_64-linux-gnu/libstdc++.so.6+0xb41e2)
#3 0x7f48d08cfd1e (/usr/lib/x86_64-linux-gnu/libstdc++.so.6+0xb1d1e)
#4 0x7f48d08b1f2d (/usr/lib/x86_64-linux-gnu/libstdc++.so.6+0x93f2d)
#5 0x7f48d16d60f5 in writeToFile() /home/daniel/programming/test/santest.cpp:10
#6 0x7f48d16d61f4 in main /home/daniel/programming/test/santest.cpp:15
#7 0x7f48d0261de4 (/lib/x86_64-linux-gnu/libc.so.6+0x21de4)
#8 0x7f48d16d5e42 in _start (/home/daniel/programming/test/a.out+0x61e42)
SUMMARY: MemorySanitizer: use-of-uninitialized-value ??:0 ??
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我怎样才能正常工作?
Clang版本3.5,stdlibc ++版本6
目前最简单的方法是使用memorysanitizer构建libc ++,然后将程序链接到它.
这是我前一段时间做的,未能处理libc ++构建系统:https: //code.google.com/p/memory-sanitizer/source/browse/bootstrap/build_libcxx.sh
我听说libc ++方面有了改进,也许可以像往常一样构建它(比如CC =/path/to/clang CFLAGS = -fsanitize = memory).