mor*_*aud 3 java arrays random
什么是对数组中单词的字母进行洗牌的最简单方法?我在数组中有一些单词,我随机选择一个单词,但我也想把它的字母洗牌.
public static void main (String[] args ) {
String [] animals = { "Dog" , "Cat" , "Dino" } ;
Random random = new Random();
String word = animals [random.nextInt(animals.length)];
System.out.println ( word ) ;
//I Simply want to shuffle the letters of word
}
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我不应该使用那个列表的东西.我想出了类似的东西,但是用这个代码打印随机字母,它不会随机播放.如果那封信已经打印出来,也许我可以编写类似不打印的东西?
//GET RANDOM LETTER
for (int i = 0; i< word.length(); i++ ) {
char c = (word.charAt(random.nextInt(word.length())));
System.out.print(c); }
}
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真的不需要收集以及以下内容:
public static void main(String[] args) {
// Create a random object
Random r = new Random();
String word = "Animals";
System.out.println("Before: " + word );
word = scramble( r, word );
System.out.println("After : " + word );
}
public static String scramble( Random random, String inputString )
{
// Convert your string into a simple char array:
char a[] = inputString.toCharArray();
// Scramble the letters using the standard Fisher-Yates shuffle,
for( int i=0 ; i<a.length ; i++ )
{
int j = random.nextInt(a.length);
// Swap letters
char temp = a[i]; a[i] = a[j]; a[j] = temp;
}
return new String( a );
}
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