如何在构造函数中调用实体管理器?

Man*_*olo 12 php constructor entitymanager symfony

我一直在尝试调用Entity Manager构造函数:

function __construct()
{
    $this->getDoctrine()->getEntityManager();
    ...
Run Code Online (Sandbox Code Playgroud)

但是,正如我在这个答案中看到的:Stackoverflow问题,它无法完成.

所以我想知道是否有办法实现它,因为我必须经常调用它,并希望在获取存储库后在构造函数中做一些事情.

编辑:

我试过@MKhalidJunaid回答:

//src/MSD/HomeBundle/Resources/config/services.yml
services:
  imageTransController.custom.service:
    class:  MSD\HomeBundle\Controller\ImageTransController
    arguments: 
        EntityManager: "@doctrine.orm.entity_manager"
Run Code Online (Sandbox Code Playgroud)

-

//app/config/config.php
imports:
- { resource: parameters.yml }
- { resource: security.yml }
- { resource: doctrine_extensions.yml }
- { resource: "@MSDHomeBundle/Resources/config/services.yml" }
Run Code Online (Sandbox Code Playgroud)

-

//src/MSD/HomeBundle/Controller/ImageTransController.php
namespace MSD\HomeBundle\Controller;

use Doctrine\ORM\EntityManager;
use MSD\HomeBundle\Entity\Imagen as Imagen;
use MSD\HomeBundle\Controller\HomeController as HomeController;


class ImageTransController extends HomeController
{
    protected $em ;

    function __construct(EntityManager $entityManager)
    {
    ...
Run Code Online (Sandbox Code Playgroud)

但我收到这个错误:

Catchable Fatal Error: Catchable Fatal Error: Argument 1 passed to MSD\HomeBundle\Controller\ImageTransController::__construct() must be an instance of Doctrine\ORM\EntityManager, none given, called in /home/manolo/MiServer/itransformer/app/cache/dev/jms_diextra/controller_injectors/MSDHomeBundleControllerImageTransController.php on line 13 and defined in /home/manolo/MiServer/itransformer/src/MSD/HomeBundle/Controller/ImageTransController.php line 38 (500 Internal Server Error)
Run Code Online (Sandbox Code Playgroud)

新尝试:

我也试过@praxmatig回答:

//services.yml
parameters:
 msd.controller.imagetrans.class: MSD\HomeBundle\Controller\ImageTransController

services:
  msd.imagetrans.controller:
    class:  "%msd.controller.imagetrans.class%"
    arguments: [ @doctrine.orm.entity_manager  ]
Run Code Online (Sandbox Code Playgroud)

-

//ImageTransController.php
namespace MSD\HomeBundle\Controller;

 use Doctrine\ORM\EntityManager;

class ImageTransController 
 {
    protected $em ;

    function __construct(EntityManager $em)
    {
        $this->em = $em;
    }
     ...
Run Code Online (Sandbox Code Playgroud)

-

//routing.yml
msd_home_cambiardimensiones:
    pattern: /cambiardimensiones
    defaults: { _controller: MSDHomeBundle:msd.imagetrans.controller:cambiardimensionesAction }
Run Code Online (Sandbox Code Playgroud)

但我得到这个错误:

 Unable to find controller "MSDHomeBundle:msd.imagetrans.controller" - class "MSD\HomeBundle\Controller\msd.imagetrans.controllerController" does not exist. (500 Internal Server Error)
Run Code Online (Sandbox Code Playgroud)

M K*_*aid 13

您需要为您的类提供服务,并将doctrine实体管理器作为参数传递doctrine.orm.entity_manager.Like in services.yml

services:
  test.cutom.service:
    class:  Test\YourBundleName\Yourfoldernameinbundle\Test
    #arguments:
    arguments: [ @doctrine.orm.entity_manager  ] 
        #entityManager: "@doctrine.orm.entity_manager"
Run Code Online (Sandbox Code Playgroud)

您必须在config.yml中导入services.yml

imports:
    - { resource: "@TestYourBundleName/Resources/config/services.yml" }
Run Code Online (Sandbox Code Playgroud)

然后在类的构造函数中获取实体管理器作为参数

use Doctrine\ORM\EntityManager;
Class Test {

  protected $em;

  public function __construct(EntityManager $entityManager)
  {
    $this->em = $entityManager;
  }
}
Run Code Online (Sandbox Code Playgroud)

希望这是有道理的


小智 5

将控制器注册为服务时,请勿扩展基本控制器类.有一个关于它的文件在这里

class ImageTestController
{
     private $em;

     public function __construct(EntityManager $em)
     {
         $this->em = $em;
     }

     public function someAction()
     {
         // do something with $this->em
     }
}

// services.yml
services:
    acme.controller.image_test:
        class: Acme\SomeBundle\Controller\ImageTestController

// routing.yml
acme:
    path: /
    defaults: { _controller: acme.controller.image_test:someAction }
Run Code Online (Sandbox Code Playgroud)