xwh*_*hyz 6 java spring spring-security
我正在尝试使用Spring安全性实现基于表单的身份验证.重定向工作正常:我的主页工作正常, http://localhost:8080/master/admin我被重定向到登录页面(http://localhost:8080/master/login/):
<form action="j_spring_security_check" method="POST">
<label for="username">User Name:</label>
<input id="username" name="j_username" type="text"/>
<label for="password">Password:</label>
<input id="password" name="j_password" type="password"/>
<input type="submit" value="Log In"/>
</form>
but when I submit I get 404 on address: `http://localhost:8080/master/login/j_spring_security_check`
Run Code Online (Sandbox Code Playgroud)
这是我的配置web.xml:
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
Run Code Online (Sandbox Code Playgroud)
我的root-context.xml(我重定向谷歌,以便我知道页面存在于上下文中)
<sec:http auto-config="true">
<sec:intercept-url pattern="/admin/**" access="ROLE_USER" />
<sec:form-login login-page="/login/"
authentication-failure-url="http://www.google.com" default-target-url="http://www.google.com" />
<sec:logout logout-success-url="/logout" />
</sec:http>
<sec:authentication-manager>
<sec:authentication-provider>
<sec:user-service>
<sec:user name="test" password="test" authorities="ROLE_USER, ROLE_ADMIN" />
<sec:user name="testuser" password="testuserpassword"
authorities="ROLE_USER" />
</sec:user-service>
</sec:authentication-provider>
</sec:authentication-manager>
Run Code Online (Sandbox Code Playgroud)
我已经失去了很多时间,尝试不同的组合,但没有运气.任何帮助表示赞赏!
| 归档时间: |
|
| 查看次数: |
13738 次 |
| 最近记录: |