通过某些列mysql查询计算正值和负值组的数量

sto*_*Boi 4 mysql count

我有以下mysql表的布局:

+------+-------+-----+------+
| user |subject|month|change|
+------+-------+-----+------+
|Donald| Math  | Jan | 3.15 |
+------+-------+-----+------+
| Mike | Math  | Jan | 2.15 |
+------+-------+-----+------+
|Regan | Math  | Jan | 3.00 |
+------+-------+-----+------+
|Donald| Engl  | Febr|-3.05 |
+------+-------+-----+------+
| Mike | Engl  | Febr| 3.00 |
+------+-------+-----+------+
|Regan | Engl  | Febr|-3.00 |
+------+-------+-----+------+
|Donald| Geog  | Jan | 3.00 |
+------+-------+-----+------+
| Mike | Geog  | Jan |-2.15 |
+------+-------+-----+------+
|Regan | Geog  | Jan | 3.60 |
+------+-------+-----+------+
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我必须按主题统计正面或负面的变化,同时得到该组的名称.如果我像这样查询mysql表:

COUNT (*) FROM $table WHERE change>0 GROUP BY subject
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它只会按主题列计算正变化(> 0)组的数量.无法获得负面更改次数(<0)并获取组名称(Math,Eng&Geog).

我希望结果应该是这样的:

===============
Group | >0| <0|
===============
 Math | 3 | 0 | 
---------------
 Eng  | 1 | 2 |
---------------
 Geog | 2 | 1 |
---------------
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什么是单个mysql查询才能获得上面的结果?

Joh*_*Woo 8

下面的查询将按记录分组subject.MySQL支持布尔运算,因为a.change > 0返回1表示true,0表示false表示.

SELECT  a.Subject,
        SUM(a.change > 0) `> 0`,
        SUM(a.change < 0) `< 0`
FROM    tableName a
GROUP   BY a.Subject
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请注意,它不包括主题change = 0.

  • 简单,优雅.好答案. (2认同)