我正在尝试显示存储在数据库中BLOB列中的图像;
我从数据库中获取数据,使用SELECT对数据执行无变换,并使用以下内容显示它(来自脚本,其唯一输出如下):
header("Content-Type: image/jpeg");
echo $image;
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请注意,chrome将内容大小显示为图像的正确大小以及正确的mime类型(image/jpeg).在标题之前没有任何回声,我已经检查了数据库中的blob是否正确.<?php ?>标签之前或之后也没有尾随空格.
chrome/IE显示图像图标,但不显示图像本身.有任何想法吗?
编辑:图像是从数据库中得到的:
$sql = "SELECT * FROM products WHERE id = $id";
$sth = $db->query($sql);
$row = $sth->fetch();
$image = $row['image'];
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var_dump($ image)给出:
string 'ÿØÿà?JFIF??x?x??ÿá?ZExif??MM?*???????????J????????Q???????Q??????tQ??????t?????† ??±ÿÛ?C?
ÿÛ?CÿÀ?_"?ÿÄ???????????
ÿÄ?µ???}?!1AQa"q2‘¡#B±ÁRÑð$3br‚
%&'()*456789:CDEFGHIJSTUVWXYZcdefghijstuvwxyzƒ„…†‡ˆ‰Š’“”•–—˜™š¢£¤¥¦§¨©ª²³ ´µ¶·¸¹ºÂÃÄÅÆÇÈÉÊÒÓÔÕÖרÙÚáâãäåæçèéêñòóôõö÷øùúÿÄ????????'... (length=60766)
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Riz*_*ani 115
试试这样.
用于插入DB
$db = mysqli_connect("localhost","root","","DbName"); //keep your db name
$image = addslashes(file_get_contents($_FILES['images']['tmp_name']));
//you keep your column name setting for insertion. I keep image type Blob.
$query = "INSERT INTO products (id,image) VALUES('','$image')";
$qry = mysqli_query($db, $query);
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用于从Blob访问图像
$db = mysqli_connect("localhost","root","","DbName"); //keep your db name
$sql = "SELECT * FROM products WHERE id = $id";
$sth = $db->query($sql);
$result=mysqli_fetch_array($sth);
echo '<img src="data:image/jpeg;base64,'.base64_encode( $result['image'] ).'"/>';
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希望它会对你有所帮助.
谢谢.
Ari*_*osh 13
这是我用来显示blob图像的方法:
echo '<img src="data:image/jpeg;base64,'.base64_encode($image->load()) .'" />';
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