Chr*_*ris 23 automation accessibility objective-c ios
可访问性标识符是开发人员为GUI对象生成的ID,可用于自动化测试.
A UIBarButtonItem没有实现UIAccessibilityIdentification.但是有可能我可以分配一个辅助功能标识符吗?
Don*_*uel 15
我们可以说,你可以在子类中继承UIBarButtonItem和实现UIAccessibilityIdentification协议BarButtonWithAccesibility.
在BarButtonWithAccesibility.h:
@interface BarButtonWithAccesibility : UIBarButtonItem<UIAccessibilityIdentification>
@property(nonatomic, copy) NSString *accessibilityIdentifier NS_AVAILABLE_IOS(5_0);
遵守此协议的唯一(严格)要求是定义accessibilityIdentifier属性.
现在在你的视图控制器中,让我们说viewDidLoad,你可以设置一个UIToolbar并添加你的子类UIBarButtonItem:
#import "BarButtonWithAccesibility.h"
- (void)viewDidLoad{
    [super viewDidLoad];
    UIToolbar *toolbar = [[UIToolbar alloc]  initWithFrame:CGRectMake(0, 0, 320, 44)];
    BarButtonWithAccesibility *myBarButton = [[BarButtonWithAccesibility alloc] initWithBarButtonSystemItem:UIBarButtonSystemItemDone target:self action:@selector(buttonPressed:)];
    myBarButton.accessibilityIdentifier = @"I am a test button!";
    toolbar.items = [[NSArray alloc] initWithObjects:myBarButton, nil];
    [self.view addSubview:toolbar];
}
在buttonPressed:您可以验证您有权访问accessibilityIdentifier:
- (void)buttonPressed:(id)sender{
    if ([sender isKindOfClass:[BarButtonWithAccesibility class]]) {
        BarButtonWithAccesibility *theButton = (BarButtonWithAccesibility *)sender;
        NSLog(@"My accesibility identifier is: %@", theButton.accessibilityIdentifier);
    }
}
希望这可以帮助.
从 iOS 5 开始,您可以这样做:
UIBarButtonItem *btn = [[UIBarButtonItem alloc] init...;
btn.accessibilityLabel = @"Label";
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