-1 java
嗨,我正在制作披萨项目,并希望用户只选择1个基地,所以一旦他说是薄的,那么厚基地就没有问题了.
System.out.print("\nDo you want thick base?");
input = keyboard.nextLine();
choice = input.charAt(0);
if (choice == 'y'){
pizza.setPizzaBase(new PizzaBase("thick"));
}
//Thin base
System.out.print("\nDo you want thin base?");
input = keyboard.nextLine();
choice = input.charAt(0);
if (choice == 'y') {
pizza.setPizzaBase(new PizzaBase("thin"));
}
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一个美好而简单的其他陈述!
System.out.print("\nDo you want thick base?");
input = keyboard.nextLine();
choice = input.charAt(0);
if (choice == 'y'){
pizza.setPizzaBase(new PizzaBase("thick"));
} else {
//Thin base
System.out.print("\nDo you want thin base?");
input = keyboard.nextLine();
choice = input.charAt(0);
if (choice == 'y') {
pizza.setPizzaBase(new PizzaBase("thin"));
}
}
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