如何使用GSON反序列化Map <String,Object>

Question

我是GSON的新手,并获得了这种格式的JSON响应(只是一个更简单的例子,因此值没有意义):

{
    "Thomas": {
        "age": 32,
        "surname": "Scott"
    },
    "Andy": {
        "age": 25,
        "surname": "Miller"
    }
}

我希望GSON使它成为一个Map,PersonData显然是一个Object.名称字符串是PersonData的标识符.

正如我所说,我对GSON很新,只尝试过类似的东西:

Gson gson = new Gson();
Map<String, PersonData> decoded = gson.fromJson(jsonString, new TypeToken<Map<String, PersonData>>(){}.getType());

但这引发了错误:

Exception in thread "main" com.google.gson.JsonSyntaxException: java.lang.IllegalStateException: Expected BEGIN_ARRAY but was STRING at line 1 column 3141

任何帮助表示赞赏:)

Answer 1

以下适用于我

static class PersonData {
    int age;
    String surname;
    public String toString() {
        return "[age = " + age + ", surname = " + surname + "]";
    }
}

public static void main(String[] args) {
    String json = "{\"Thomas\": {\"age\": 32,\"surname\": \"Scott\"},\"Andy\": {\"age\": 25,\"surname\": \"Miller\"}}";
    System.out.println(json);
    Gson gson = new Gson();
    Map<String, PersonData> decoded = gson.fromJson(json, new TypeToken<Map<String, PersonData>>(){}.getType());
    System.out.println(decoded);
}

和打印

{"Thomas": {"age": 32,"surname": "Scott"},"Andy": {"age": 25,"surname": "Miller"}}
{Thomas=[age = 32, surname = Scott], Andy=[age = 25, surname = Miller]}

所以也许你的PersonData班级非常不同.