我想为包含计数的模型创建一个属性.
因为我总是需要的财产,我想使查询与JOIN类似sqlalchemy.orm.relationship与lazy='joined'
例如,我定义了如下的模型
import sqlalchemy as s, func
from sqlalchemy.orm import relatioship
# ...
class Foo(Base):
__tablename__ = 'foo'
id = s.Column(s.Integer, primary_key=True)
bar_id = s.Column(s.Integer, s.ForeignKey('bar.id'))
bar = relationship('Bar')
class Bar(Base):
__tablename__ = 'bar'
id = s.Column(s.Integer, primary_key=True)
@property
def foo_count(self):
return Foo.query.filter_by(bar=self).count()
Run Code Online (Sandbox Code Playgroud)
当我访问属性时foo_count,它会向DBMS发送查询.
因为我总是访问这个属性,我想急切地加载它这样的计数属性
# Not session.query(Bar, func.count(Foo.id)).join(Foo) ...
bar = Bar.query.first()
Run Code Online (Sandbox Code Playgroud)
SQL将是这样的
SELECT id, COUNT(Foo.id)
FROM bar
INNER JOIN foo
ON bar.id = foo.id
Run Code Online (Sandbox Code Playgroud)
然后bar.foo_count就不会发生SQL查询.
我该如何制作一个属性foo_count?
Cho*_*onu 10
我用它来解决它 sqlalchemy.orm.column_property
我替换了foo_count以下
import sqlalchemy as s, func, select
from sqlalchemy.orm import relationship, column_property
# ...
class Foo(Base):
__tablename__ = 'foo'
id = s.Column(s.Integer, primary_key=True)
bar_id = s.Column(s.Integer, s.ForeignKey('bar.id'))
bar = relationship('Bar')
class Bar(Base):
__tablename__ = 'bar'
id = s.Column(s.Integer, primary_key=True)
foo_count = column_property(
select([func.count(Foo.id)])
.where(Foo.bar_id == id)
)
Run Code Online (Sandbox Code Playgroud)
请查看Hybrid Attribute扩展.
您的对象模型将类似于以下内容:
class Foo(Base):
__tablename__ = 'foo'
id = Column(Integer, primary_key=True)
bar_id = Column(Integer, ForeignKey('bar.id'))
bar = relationship('Bar')
class Bar(Base):
__tablename__ = 'bar'
id = Column(Integer, primary_key=True)
@hybrid_property
def foo_count(self):
return object_session(self).query(Foo).filter(Foo.bar==self).count()
@foo_count.expression
def foo_count(cls):
return select([func.count(Foo.id)]).where(Foo.bar_id == cls.id).label('foo_count')
Run Code Online (Sandbox Code Playgroud)
foo_count不会急切加载,但你可以在下面的查询中使用它(在in SELECT和in WHERE子句中:
qry = session.query(Bar, Bar.foo_count).filter(Bar.foo_count > 0)
for (bar, bar_foo_count) in qry:
print bar, bar_foo_count
Run Code Online (Sandbox Code Playgroud)
正如您所看到的,查询将仅返回(Bar, foo_count)一个查询中的元组,现在您可以使用该查询执行所需的操作.
| 归档时间: |
|
| 查看次数: |
2411 次 |
| 最近记录: |